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Uniform stability implies expected generalization
Statement
Let and consider a supervised prediction problem with measurable observation space , probability law , measurable predictor class , and nonnegative measurable loss . For and , write , , and, for , . Let be IID with law , and let be internal randomness independent of the sample. Suppose the randomized learning rule takes values in , the joint loss map is measurable, and all displayed risks are integrable. If has uniform replacement stability at level , then
The expectation is over both the IID sample and the algorithm's internal randomness. No permutation-invariance assumption on is required.
Statement references
Hardt, Recht, and Singer, Theorem 2.2 and proof: full arXiv paper.
Matni, Lecture 16, Theorem 2 and proof: full lecture notes.
Facts & Assumptions
Given: The supervised prediction problem, IID sample, independent algorithmic randomness, measurable and integrable loss maps, and uniform replacement stability in the Statement.
Supervised prediction problems: the joint observation law is a probability measure and the loss is nonnegative and measurable.
Population and empirical risk: population risk is the nonnegative integral of test loss and empirical risk is its finite sample average.
Identical distribution and IID families: the observations are mutually independent and have common law .
An IID sample and ghost point are exchangeable: if is an independent observation with law , then and have the same law for each , where replaces coordinate by .
Fubini's theorem for L^1 functions on a sigma-finite product: for the integrable joint loss map, its product integral equals either iterated integral, including integration over the independent algorithm seed and test observation.
The Lebesgue integral is linear on : the integral of a finite sum of integrable functions is the sum of their integrals.
The modulus of an integral is bounded by the integral of the modulus: the absolute value of an integral is at most the integral of the absolute value.
Uniform stability for randomized learning rules: for every fixed adjacent pair of ordered samples and test observation, the difference of their expected losses over has absolute value at most .
The joint loss map is measurable and integrable, as required in the Statement, so Fubini and every displayed expectation are defined.
Proof
Extend the sample by an independent ghost observation . By [F1], [F2], and [F5], . For each , [F4] and independence of imply .
By [F2] and [F6], subtracting the expected empirical risk and averaging the equalities in step 1.1 gives For every fixed , the samples and differ in one coordinate, so [F8] bounds the absolute value of the inner expectation over by . Applying [F7] to the outer expectations and then averaging gives the claimed absolute bound.
Depends on
- Uniform stability for randomized learning rules
- An IID sample and ghost point are exchangeable
- Supervised prediction problems
- Population and empirical risk
- Identical distribution and IID families
- Expectation of a nonnegative or integrable random variable
- Integrable real and complex functions, and their integrals
- Fubini's theorem for L^1 functions on a sigma-finite product
- The Lebesgue integral is linear on $L^1(\mu)$
- The modulus of an integral is bounded by the integral of the modulus
Used by
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Sources
- Moritz Hardt, Benjamin Recht, and Yoram Singer, Train faster, generalize better: Stability of stochastic gradient descent, Theorem 2.2 and proof (standard reference, not scraped)
- Nikolai Matni, ESE680 Lecture 16: Algorithmic Stability and Stochastic Gradient Descent, Theorem 2 and proof (standard reference, not scraped)