Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
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Subextremal RN surface gravity has no uniform positive lower bound

Statement refuted

Fix a mass length m>0. For each length parameter qe∈R with 0<qe2<m2, take the electric RN family with mass parameter M=m and magnetic parameter qm=0, and define Q2:=qe2, r±:=m±m2−Q2, and κ+(qe):=(r+−r−)/(2r+2). The false claim is that there exists a constant c>0, with units of inverse length, such that κ+(qe)≥c for every such qe.

Facts & Assumptions

Given: A fixed m>0 and the subextremal electric RN family with qm=0 and 0<qe2<m2.

[F1]

Dyonic Reissner-Nordström metric and field domains: Q2=qe2+qm2 and the static RN metric uses f(r)=1−2m/r+Q2/r2.

[F2]

RN roots, Killing horizons and surface gravity: when m>0 and Q2>0, the outer surface gravity is κ+=(r+−r−)/(2r+2) with r±=m±m2−Q2.

[F3]

Explicit rational and real power regimes: for a>0, a is the unique positive real solution of s2=a.

[F4]

Dedekind-complete ordered real field: R is a complete ordered field.

[F5]

For every ε>0 in a complete ordered field there is a natural n≥1 with 1/n<ε: in any complete ordered field, for every ϵ>0 there is a natural N≥1 with 1/N<ϵ.

[A1]

The fixed mass parameter satisfies m>0; all mass and charge parameters have length units and κ+ has inverse-length units.

Counterexample

1.1givenA1F1F2F3algebra

For each integer n≥2, choose qe,n=m1−n−2 and qm,n=0. By [F3], Qn2=qe,n2=m2(1−n−2), so 0<Qn2<m2 and m2−Qn2=m/n. Applying [F2] gives r+,n=m(1+1/n), r−,n=m(1−1/n), and κ+,n=r+,n−r−,n2r+,n2=nm(n+1)2,0<κ+,n<1mn.

2.1givenA1F4F5step 1.1algebra∎

Let c>0 be any proposed inverse-length lower bound. Since mc>0, [F4]–[F5] allow a natural N≥1 with 1/N<mc. For every integer n≥2N, 1/n≤1/(2N)<mc, so step 1.1 gives 0<κ+,n<1/(mn)<c. Thus the sequence κ+,n tends to zero through subextremal RN data, contradicting any positive uniform lower bound. Every member of the sequence remains subextremal; only its limit reaches Q2=m2.

Remarks

The counterexample concerns the unscaled outer surface gravity as the charge approaches extremality at fixed mass. It makes no claim about the scaled throat coordinates or about uniform estimates for waves.

Depends on

Dependency tree · 2 levels

Sources