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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Constant-density profile has unequal pressures at equal energy density

Statement refuted

For this item, a differentiable barotropic pressure law is a C1 map P:Jϵ→R, where Jϵ⊂(0,∞) is an open interval of energy-density values containing ϵ0, both input energy density and output pressure have units J m−3, and p(r)=P(ϵ(r)) for each interior radius 0≤r<R. The finite causal-slope criterion under consideration is 0≤P′(x)≤1 for x∈Jϵ, so P′ is dimensionless. For units only, set the formal parameter cs2:=c2P′(x), with units m2 s−2; this item assigns no fluid-dynamical meaning to it and makes no claim about an observed signal speed.

The claim refuted is that every regular static constant-density solution supplies such a map P satisfying this slope criterion.

Facts & Assumptions

Given: The exact constant-density branch of Exact regular constant-density solution with verified matching, under ZF+ACω as in The Axiom of Countable Choice (ACω). The slope bound is a stipulated mathematical condition on the candidate map P; no fluid evolution equation or empirical signal-speed interpretation is assumed.

[F1]

On the branch of Exact regular constant-density solution with verified matching, a=1−u, B(r)=1−ur2/R2, b(r)=B(r)2, and p(r)=ϵ0(B(r)−a)/(3a−B(r)) for 0≤r≤R; the interior energy density is ϵ0. At u=1/2, a=1/2, B(0)=1, B(R/2)=7/8, and a≤B(r)≤1. Hence 3a−B(r)≥3/2−1>0 throughout the interior, and p(0)=ϵ0(1−a)/(3a−1)>0 (Exact regular constant-density solution with verified matching).

[A1]

The geometric supplier chain uses exactly ACω as defined in The Axiom of Countable Choice (ACω), with no full Axiom of Choice. The slope bound in the refuted claim is a stipulated mathematical criterion; no fluid evolution equation is assumed.

Counterexample

1.1A1F1constructalgebra

Choose u=1/2. The center and the interior point r=R/2 both have energy density ϵ0, while their pressures differ. By [F1], B(0)=1>B(R/2)=7/8>1/2=a; the denominators 3a−B(0) and 3a−B(R/2) are positive. Subtracting the exact pressure formulas gives p(0)−p(R/2)ϵ0=2a(B(0)−B(R/2))(3a−B(0))(3a−B(R/2))>0, so p(0)>p(R/2)>0.

2.1givenA1F1step 1.1contradiction∎

If a single-valued relation p=P(ϵ) described this full static configuration, it would require both P(ϵ0)=p(0) and P(ϵ0)=p(R/2), contradicting p(0)>p(R/2). Thus the static solution does not supply a single-valued map P satisfying the stated relation, so no value of P′(ϵ0), finite sound-speed parameter, or causal bound can be inferred from this solution alone.

Remarks

The interior profile assigns the same energy density ϵ0 to every interior radius while the pressure varies. Thus pressure is not a single-valued function of energy density along this profile; this does not imply an infinite or superluminal signal speed.

Depends on

Dependency tree · 2 levels

Sources