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Uniqueness of finite Borel measures from their Fourier transforms

Statement

Assume AC. Finite complex Borel measures μ,ν on Rn with μ^=ν^ are equal. Here finite means finite total variation, and n≥1.

Facts & Assumptions

Given: The stated measures and The Axiom of Choice.

[F1]

Gaussian smoothing has transform k^tσ^ and converges against all compactly supported continuous tests (Gaussian smoothing of finite measures).

[F2]

The integral Fourier transform is injective on L1 (Uniqueness of the L1 Fourier transform).

[F3]

A compact-finite Borel measure on a second-countable LCH space is regular (Locally finite Borel measures on second-countable LCH spaces are regular).

[F4]

Positive Radon measures agreeing on every compactly supported continuous test are equal (Assuming Dependent Choice, uniqueness of the RMK representing measure among Radon measures).

Proof

1.1F1F2given

Set σ=μ−ν. It is a complex measure and its partition sums are bounded by ∣μ∣+∣ν∣, so it has finite variation. Linearity of the bounded-test integrals gives σ^=0. For every t>0, F1 gives a density ht∈L1 with zero transform; F2 gives ht=0 almost everywhere. Passing to the F1 testing limit yields ∫φ dσ=0 for every complex φ∈Cc.

2.1F3F5F6step 1.1

Euclidean space is Hausdorff (disjoint small balls separate points) and locally compact by compact closed balls from F6. Balls with rational centers and positive rational radii form a countable base: for an open neighborhood of x choose a sufficiently small contained ball, then a rational center sufficiently near x and rational radius between the resulting strict bounds. Thus F3 applies to the finite positive measure v=∣σ∣ and makes it regular. Under AC, F5 gives Jordan parts r+,r− of r=Re⁡σ and s+,s− of s=Im⁡σ. On their respective Hahn sets, for example r+(E)=r(E∩P)≤∣σ(E∩P)∣≤v(E); the same argument bounds each other part by v.

3.1F4F5step 1.1step 2.1∎

If 0≤ρ≤v is one of these parts and E is Borel, regularity of finite v gives compact K⊆E and open U⊇E with v(E∖K)<ϵ and v(U∖E)<ϵ. The corresponding rho errors are at most these, so rho is both inner and outer regular and finite on compact sets, hence Radon. For real φ∈Cc, step 1.1 gives ∫φ dr+=∫φ dr− and the analogous equality for s. These component integral identities follow for simple tests and then by their bounded-test approximation. F4 gives r+=r− and s+=s−, so σ=0. AC is used in smoothing and the Hahn/Jordan decompositions, and covers the regularity construction.

Depends on

Dependency tree · 2 levels

Sources