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Higher Zhu quotients and candidate products

Definition

Let V=⨁r≥0Vr be a conformal vertex algebra of CFT type. For each integer n≥0 and homogeneous u,v∈V, define u∘nv=Res⁡zY(u,z)v (1+z)wt(u)+nz2n+2,Du=L(−1)u+L(0)u,On(V)=span⁡C{u∘nv,  Du:u,v∈V}. Define the candidate operation on representatives u∗nv=∑m=0n(−1)m(m+nn)Res⁡zY(u,z)v (1+z)wt(u)+nzn+m+1. Extend ∘n and ∗n uniquely to bilinear maps V×V→V by summing over the finite homogeneous decompositions of both inputs; D=T+L(0) is linear. The span defining On(V) uses these extensions. Write An(V)=V/On(V) for the vector-space quotient; the operation ∗n descends to an associative unital algebra only under the separate theorem cited below. At n=0 the extra span D(V) is redundant and the formulas reduce to the Zhu circle subspace and candidate product.

Facts & Assumptions

Given: V is a conformal vertex algebra of CFT type in the non-super state–field convention.

[F1]

Conformal vertex algebra of CFT type: T=L(−1), homogeneous weights are nonnegative integers, and L(0)u=wt(u)u for homogeneous u.

[F2]

Vertex algebra in the state–field convention: Y(u,z)v=∑j∈Zu(j)v z−j−1 and the vacuum/creation axiom is Y(u,z)1=ezTu.

Proof

1.1givenF1F2algebra

For fixed n≥0 and homogeneous u of weight r, the exponent r+n is a nonnegative integer. The two residue formulas are therefore finite sums: u∘nv=∑j=0r+n(r+nj)u(j−2n−2)v,u∗nv=∑m=0n∑j=0r+n(−1)m(m+nn)(r+nj)u(j−n−m−1)v. Thus every displayed vector lies in V, and On(V) is a vector subspace.

2.1givenF1F2step 1.1algebra∎

For homogeneous u, the creation axiom and the finite binomial expansion give u∘01=Res⁡zezTu (1+z)wt(u)z−2=Tu+wt(u)u=L(−1)u+L(0)u=Du. Hence D(V)⊆span⁡{u∘0v} and O0(V) equals the ordinary Zhu circle subspace. The n=0 candidate operation is the ordinary Zhu star operation.

Proof status

This definition fixes the higher Zhu quotient as in DLM §2, including the additional D(V) summand needed for the algebra theorem. It defines a vector quotient and a candidate operation only; associativity and descent are not implicit.

Depends on

Dependency tree · 2 levels

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