Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A closed field on a star-shaped domain with its radial primitive computed

Example

On U=R2, which is star-shaped about the origin (Star-shaped open subsets of Euclidean space), consider the C1 field F(x,y):=(2xy, x2) (Exact and closed C1 vector fields). Its potential

ϕ(x,y):=x2y

has gradient ∇ϕ=(2xy,x2)=F, so F is exact with potential ϕ. The closed field condition ∂1F0=∂0F1 holds as well, and the radial formula of the published Poincare lemma returns exactly ϕ:

∫01⟨F(t(x,y)),(x,y)⟩2 dt=∫013x2y t2 dt=x2y.

Facts & Assumptions

Given: The open set U=R2 with centre 0, the field F(x,y)=(2xy,x2) and the function ϕ(x,y)=x2y.

[L1]

R2 is open and star-shaped with respect to 0: for every x∈R2 and 0≤t≤1 the point tx lies in R2 (Star-shaped open subsets of Euclidean space).

[L2]

A C1 field F=(F0,F1) on an open subset of R2 is closed when ∂1F0=∂0F1, and exact when there is a C2 function ϕ with ∇ϕ=F (Exact and closed C1 vector fields).

[L3]

Poincare's lemma: on a star-shaped open domain U with centre a, every closed C1 field is exact, and a C2 potential is ϕ(x)=∫01⟨F(a+t(x−a)),x−a⟩2 dt (Poincare's lemma on a star-shaped domain: every closed C1 field is exact).

Verification

technique · direct; compute the partial derivatives and evaluate the radial integral
1.1givenL2algebra

The component functions F0(x,y)=2xy and F1(x,y)=x2 are C1, with ∂1F0=2x=∂0F1; hence F is closed by [L2].

2.1step 1.1L2algebra

The function ϕ(x,y)=x2y is C2 with ∂0ϕ=2xy=F0 and ∂1ϕ=x2=F1, so ∇ϕ=F and F is exact with potential ϕ by [L2].

3.1step 2.1L1L3L4algebra∎

For a=0 the radial formula of [L3] reads ϕrad(x,y)=∫01⟨F(tx,ty),(x,y)⟩2 dt=∫01(2t2x2y+t2x2y)dt=∫013x2yt2 dt. The integrand is a continuous polynomial on [0,1], hence Riemann integrable by [L4]. By [L4] applied to G(t):=x2yt3, whose derivative is 3x2yt2, the integral equals G(1)−G(0)=x2y, so ϕrad=ϕ.

Remarks

  • The example exercises the exactness side of Poincare's lemma on the whole plane. Exactness is not a consequence of closedness on domains with holes: the standard angular field on R2∖{0} is closed but has no global primitive, a result established separately in the published counterexample cex-the-closed-angular-form-on-the-punctured-plane-is-not-exact, which is not used as a premise here.

  • Both displays agree on the potential because the radial formula is an explicit construction, not an independent existence argument; the differentiation check of step 2.1 is what identifies ϕ as a potential.

Depends on

Dependency tree · 2 levels

Sources