Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-23 (gpt-6.1-sol)
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Constant velocity has zero subfilter stress

Example

Assume the Axiom of Countable Choice required by the normalized periodic torus convention. Let d∈{1,2,3}, L>0 m, I⊆R an open time interval measured in s, w∈Rd a constant velocity measured in m s−1, and constant kinematic viscosity ν>0 measured in m2 s−1. Set u(x,t)=w, p(x,t)=0, and f(x,t)=0 on TLd×I. Use the dimensional incompressible equation ∂tu+∇⋅(u⊗u)+∇p=νΔu+f, with pressure per unit mass p and force per unit mass f, where ∇⋅(u⊗v)i=∑j∂j(uivj) and Δ=∑j∂j2. This is a smooth divergence-free solution. For every 0<ℓ<L/2, the positive periodic convolution filter gives u‾ℓ=w, τℓ=0, and Πℓ=0. Every velocity increment vanishes, so the Hölder transfer estimate applies with A(t)=0 and has zero right-hand side. This is an exact mathematical example, not a reported observation.

Facts & Assumptions

Given: The constant fields and parameters in the example.

[A1]

The adopted mathematical system is ∂tu+∇⋅(u⊗u)+∇p=νΔu+f with ∇⋅u=0.

[A2]

Adopt Countable Choice: every countable family of nonempty sets has a choice function (The Axiom of Countable Choice (ACω)); the Fourier-Sobolev torus convention is stated and proved under this axiom.

[F1]

Positive periodic convolution filter and subfilter stress: the filter has a nonnegative unit-mass kernel, τℓ=u⊗u‾ℓ−u‾ℓ⊗u‾ℓ, and Πℓ=−τℓ:∇u‾ℓ.

[F2]

Hölder bound for filtered subfilter energy transfer: under the stated periodic Hölder increment hypothesis, ∣Πℓ∣≤Cd,K,αA3ℓ3α−1.

Verification

technique · direct

Given: u(x,t)=w, p=0, f=0, and the filter width satisfies 0<ℓ<L/2.

1.1givenA1algebra

Every spatial and time derivative of u vanishes, so ∇⋅u=0, ∂tu=0, ∇⋅(u⊗u)=0, and Δu=0. Thus [A1] holds with p=f=0 for every ν>0.

2.1A2F1step 1.1algebra

Since the kernel has unit mass, filtering the constant field gives u‾ℓ=w and filtering u⊗u=w⊗w gives u⊗u‾ℓ=w⊗w. Hence τℓ=0, ∇u‾ℓ=0, and Πℓ=0.

3.1A2F2step 2.1algebra∎

For all s,x,t, u(x−ℓs,t)−u(x,t)=0, so the Hölder condition holds with A(t)=0 for any 0<α<1. Applying [F2] yields ∣Πℓ∣≤0, consistent with the exact value in step 2.1.

Depends on

Dependency tree · 2 levels