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Explicit stationary weak-field data with a dimensionless quadratic potential: exact Poisson source and the first-order Einstein coefficient

Example

Work on the flat model of The flat model spacetime: the Minkowski metric on R^4 and its inertial chart with inertial chart x, let L>0 be a length, take spacetime region Ω=R×BL(0)⊆R4 with spatial base U=BL(0)⊆R3, and let K=B‾L/2(0)⊂U. Set c>0, GN>0, κ:=8πGN/c4, C:=1, ε0:=1/2, choose the stationary-data remainder interval parameter ε1data:=1, set r≡0 on that interval, and

φ(x):=(x1)2+(x2)2+(x3)22L2.

Then:

  1. (Ω,K,L,C,ε0,φ,r) is stationary weak-field data in the sense of Stationary weak-field data: the diagonal ansatz, its bounds, stationarity and the Einstein-family condition clause (a), with gab(ε)=ηab+εhab, h00=−2φ, hij=−2φδij, h0i=0; the family (δ1,h,q) with δ1:=1/2 and q≡0 is a flat linearized family and g(ε)−η=εh.

  2. Defining Tab(ε):=Gab(g(ε))/κ and ρε:=T00(ε)/c2 (The Riemann curvature operator and the derived Ricci, scalar and Einstein tensors) makes the data an Einstein family with coupling κ (Stationary weak-field data: the diagonal ansatz, its bounds, stationarity and the Einstein-family condition clause (c)). This smooth symmetric source is defined by the metric; no dust model or independent rest-mass density is asserted.

  3. For Φ=εc2φ, ΔΦ=3εc2/L2 exactly. The constant Newtonian source

    ρˉ:=3εc24πGNL2

    satisfies ΔΦ=4πGNρˉ exactly on U. The distinct coordinate density read from the Einstein-family tensor satisfies ∣ρε−ρˉ∣≤C2ε2c2/(8πGNL2) on K for 0<ε≤ε∗′, by the general 00-component hierarchy; this does not use the hierarchy theorem's independent-dust conclusion.

  4. The first-order Einstein coefficient of A(ε):=εh is

    G00(1)(A(ε))=6εL2=2ΔΦc2,G0i(1)(A(ε))=Gij(1)(A(ε))=0,

    so the leading term of the hierarchy is exactly the first-order coefficient of the family.

Facts & Assumptions

Given: The flat model with inertial chart x, spacetime region Ω=R×BL(0), spatial base U=BL(0), compact spatial set K=B‾L/2(0), the function φ and r≡0 above, C=1, ε0=1/2, ε1data=1, δ1=1/2, c>0, GN>0 and κ=8πGN/c4.

[L1]

Stationary weak-field data have metric components g00=−(1+2εφ)+r00, g0i=r0i and gij=(1−2εφ)δij+rij pulled back from U; the metric must be Lorentzian on Ω and the spatial derivatives through order two obey the stated bounds on K. An Einstein family has a smooth symmetric field T with G=κT and ρε=T00/c2 (Stationary weak-field data: the diagonal ansatz, its bounds, stationarity and the Einstein-family condition clauses (a)-(c), Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model, The Riemann curvature operator and the derived Ricci, scalar and Einstein tensors).

[L2]

For every stationary weak-field Einstein family, the general component hierarchy gives ∣κT00−2ΔΦ/c2∣≤C2ε2/L2 on K for 0<ε≤ε∗′ (The weak-field Einstein hierarchy: linearized Einstein tensor, stress components and the Poisson equation clauses (b)-(c)).

[L3]

For φ(x)=∣x∣2/(2L2), ∂iφ=xi/L2, ∂i∂jφ=δij/L2 and Δφ=3/L2; the field is stationary (The Laplacian of a C2 function and of a C2 vector field).

[L4]

The first-order formulas are linear in h and give hˉ00=−4φ, hˉ0i=hˉij=0 and Gab(1)=−12□hˉab+∂c∂(ahˉb)c−12ηab∂c∂dhˉcd; for stationary fields □=Δ (First-order curvature of a flat linearized family, gauge transformations and the quadratic remainder clause (c), Flat linearized perturbations: families, trace reversal, gauge transformation and harmonic gauge clauses (a) and (c)).

[L5]

On U=BL(0), 0≤φ<1/2; for 0<ε≤1/2 the diagonal metric entries −(1+2εφ) and 1−2εφ have signs −,+,+,+. Also κc2=8πGN/c2.

Verification

technique · check the spatially factored data, compute the exact Newtonian Poisson source and the first-order Einstein tensor, then use the general coordinate-density estimate without imposing dust assumptions
1.1L1L3L5algebra

(Admissible data.) The fields are smooth and factor through the spatial projection. For 0<ε≤1/2 and x∈U, 0≤2εφ<1/2, so [L5] gives a diagonal Lorentzian metric of signature (−,+,+,+) on all of Ω. On K, ∣φ∣≤1/8, ∣∂iφ∣≤1/(2L) and ∣∂i∂jφ∣≤1/L2, so the bounds hold with C=1; r=0 satisfies its bounds on (−ε1data,ε1data), with ε1data=1>ε0=1/2. Taking δ1=1/2 and q=0 gives the stated flat linearized family.

1.2L3L4algebra

(First-order coefficient.) By [L3], Δφ=3/L2. The trace reversal has hˉ00=−4φ and all other components zero. Formula [L4], stationarity and □=Δ give G00(1)(h)=2Δφ=6/L2 and G0i(1)(h)=Gij(1)(h)=0. Linearity gives G00(1)(A(ε))=6ε/L2 and the remaining displayed components vanish.

2.1step 1.1L1L5algebra

(Einstein family.) Define Tab(ε)=Gab(g(ε))/κ on Ω. The metric-selected connection and curvature depend smoothly on the metric and its derivatives; hence T is a smooth symmetric component field and G=κT identically. Thus the data are an Einstein family by [L1], with coordinate density ρε=T00/c2. This construction is a mathematical source prescription, not a dust realization.

3.1step 2.1L2L3L5algebra

(Exact Poisson source and coordinate-density estimate.) By [L3], ΔΦ=εc2Δφ=3εc2/L2. Defining ρˉ=3εc2/(4πGNL2) gives ΔΦ=4πGNρˉ exactly. By [L2], ∣κc2ρε−6ε/L2∣≤C2ε2/L2. Since κc2ρˉ=6ε/L2 and κc2=8πGN/c2, division by κc2>0 gives ∣ρε−ρˉ∣≤C2ε2c28πGNL2. This compares the exact Newtonian source with the relativistic coordinate density to the order established by the component hierarchy; it does not assert equality or an independent dust source.

4.1step 1.2step 3.1L4algebra∎

(Leading term.) By steps 1.2 and 3.1, G00(1)(A(ε))=6ε/L2=2ΔΦ/c2, and the other first-order Einstein components vanish as stated. This completes the verification.

Remarks

  • Non-vacuity and scope. The example exhibits a data tuple satisfying the general Einstein-component hypotheses of the hierarchy theorem with C=1 and arbitrary L>0; it asserts no independent dust realization, and computes the dictionary quantities Φ, ρˉ and G(1) for it. It is a conditional statement about the model family: it asserts that the quadratic potential solves the Poisson equation with constant density, not that any physical body realizes the density, and it involves no observation.

Depends on

Dependency tree · 2 levels

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