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The two-level inversion model in an oscillating field: resonance, averaged Rabi inversion and its error contract

Physical scope

A conditional two-level model of an inversion doublet driven by an oscillating field: the identification with the declared linear drive model, the resonance condition and the averaged Rabi inversion probability, the pulse time, and the rotating-wave error contract at the pulse time for a declared coupling ratio. The example is a declared finite model; it asserts no measured transition frequency, no laboratory molecule or cavity, no damping or relaxation, no emission rate and no measurement record.

Example

Adopt P1, P2 and P4 in the readings of the declared driven model (The declared driven model: prescribed time-dependent energy families, propagator evolution and the two-level drive models clause (a)) and the basis (∣E⟩,∣G⟩) of a declared two-level inversion model: two orthogonal unit vectors with the Pauli matrices of Finite spin matrices clause (e) acting on their span, so that σz=diag⁡(1,−1) distinguishes the two levels. Declare real parameters Δ0>0 (half the inversion splitting, joules), μ>0 (a dipole-like coupling, in C m), E0>0 (a field amplitude, in V m−1) and a drive frequency ω>0 in s−1, and declare the model's energy family H(t):=Δ0σz+2μE0cos⁡(ωt) σx,t∈R, read as the energy of the declared model, with ℏ the reduced Planck constant of Dimensions, SI unit conventions and quantity types of the framework; populations are the diagonal entries of the two projections onto C∣E⟩ and C∣G⟩ in the evolved preparation. Fix the coupling ratio x:=μE0/Δ0 (dimensionless). Then:

(a) Identification with the declared linear drive. H(t)=ℏ2(ω0σz+Ω1cos⁡(ωt)σx) with ω0=2Δ0ℏ,Ω1=4μE0ℏ,ω0∈s−1, Ω1∈s−1, so the model is an instance of the declared linear two-level drive model of clause (f) with Δ=ω0−ω; the level splitting is 2Δ0.

(b) Resonance and averaged inversion. At resonance ω=ω0, i.e. ℏω=2Δ0, the averaged model of the page's error contract predicts that the initial ∣E⟩ population is transferred to ∣G⟩ with probability pGavg(τ)=sin⁡2 ⁣(μE0τℏ), which equals 1 at the inversion time τ=πℏ/(2μE0); equivalently Ω1τ/4=π/2 at that time.

(c) Error contract at inversion. At the inversion time τ=πℏ/(2μE0) the exact ∣G⟩ population pG satisfies ∣pG−1∣≤2x(1+3π2), so with the declared ratio x=1/100 the contract gives pG≥1−2+3π100;

(d) status. The model, its parameters and the time τ are declared model data; no measured transition frequency, no laboratory molecule, cavity or field, no damping or relaxation and no measurement record appears, and the averaged formula is accompanied by the explicit contract of clause (c), not asserted as exact.

Verification

Given: the declared two-level inversion model with parameters Δ0,μ,E0,ω and coupling ratio x=μE0/Δ0; the reading of the declared linear drive model; the Axiom of Countable Choice and the Axiom of Choice as the choice hypotheses of the page's reading.

[L1] The declared linear model and its contract. The declared linear two-level drive model of clause (f) of The declared driven model: prescribed time-dependent energy families, propagator evolution and the two-level drive models has energy Hl(t)=ℏ2(ω0σz+Ω1cos⁡(ωt)σx) and detuning Δ=ω0−ω; for ω≠0, preparation ψ(s)=e↑ and forward elapsed time τ=t−s≥0 with s,t in the declared interval, its exact down-population differs from the averaged Rabi population p↓avg(τ)=((Ω1/2)2/(Δ2+(Ω1/2)2))sin⁡2(τ2Δ2+Ω12/4) by at most 2ε(τ) with ε(τ)=∣Ω1∣2∣ω∣[1+τ(∣Δ∣2+3∣Ω1∣4)] (The linearly driven two-level model: rotating-wave approximation with an explicit finite-time error contract and the averaged Rabi populations clauses (a)-(d)).

[L2] The circular companion. For the circular two-level drive model the rotating-frame reduction is exact and the down-population of the initial up-state is Ω12sin⁡2(bτ/2)/b2 with b=Δ2+Ω12 (The circularly driven two-level model: exact rotating-frame reduction, Rabi populations, resonance and inversion times clause (b)); this is recorded as the contrast case in which no rotating-wave error occurs.

[L3] Elementary arithmetic. ω0=2Δ0/ℏ and Ω1=4μE0/ℏ; at resonance Δ=0 one has ∣Ω1∣/(2∣ω∣)=Ω1/(2ω0)=(4μE0/ℏ)/(4Δ0/ℏ)=μE0/Δ0=x and 3∣Ω1∣/4=3μE0/ℏ, so ε(τ)=x(1+3μE0τ/ℏ); at τ=πℏ/(2μE0) this is x(1+3π/2) and μE0τ/ℏ=π/2.

Proof technique: direct; match the declared matrix family with the page's declared linear model, specialise the error contract to resonance, and evaluate the declared time exactly.

Given: the data of the Example and [L1]-[L3].

1.1L1givenalgebra

[Identification] Comparing H(t)=Δ0σz+2μE0cos⁡(ωt)σx with ℏ2(ω0σz+Ω1cos⁡(ωt)σx) term by term gives ℏω02=Δ0 and ℏΩ12=2μE0, i.e. the displayed ω0,Ω1; To apply the compact-interval model at any finite elapsed time τ≥0, restrict the declared all-real family to I=[s,s+τ] and prepare ψ(s)=∣E⟩=e↑ in the displayed basis. Both frequencies are in s−1 because Δ0 is in joules and ℏ in J s, and the level splitting is ℏω0=2Δ0. This is clause (a).

2.1L1L3step 1.1algebra

[Averaged inversion] At resonance ω=ω0 one has Δ=0, so the averaged formula of [L1] reads pavg=sin⁡2(τΩ1/4)=sin⁡2(μE0τ/ℏ) by [L3]; at τ=πℏ/(2μE0) the argument is π/2 and the probability is 1. This is clause (b).

3.1L1L2L3step 2.1algebra∎

[Contract at inversion] By [L1] and [L3] the error at the inversion time is 2ε=x(1+3π/2) doubled, i.e. 2x(1+3π/2), and with x=1/100 the bound is 2x(1+3π2)=2+3π100, so pG≥1−2+3π100; the population is the model's outcome probability of the ground-level projection in the evolved preparation, and the contrast case [L2] shows that the circular model of the same frequencies has no such error term. This is clauses (c) and (d).

Remarks

  • What is and is not asserted. The example asserts a conditional model statement: the declared two-level family has a resonance at ℏω=2Δ0 at which the averaged model inverts the population at the time πℏ/(2μE0), with an explicit error contract. It does not assert that any molecule, cavity or field realizes these parameters, and it records no measured frequency; the source's reported numerical frequency is not used as a premise.
  • Why the contract is needed. The source treatment drops the counter-rotating term; the contract of clause (c) is what makes that step quantitative, and the ratio x=μE0/Δ0 is exactly the small parameter controlling it.

Depends on

Dependency tree · 2 levels

Sources