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The Borel and Cartan cohomology of a point

Example

Assume AC and let T=R/Z act trivially on the one-point smooth manifold {∗}. Use the period-one tangent generator and its selected degree-two polynomial generator u. In the chosen Borel model, HT∗({∗};R)≅R[u], with ∣u∣=2. The Cartan complex is R[u] with zero differential, so its cohomology is also R[u] under the selected coefficient normalization.

Example references

[Borel and Cartan definitions and cohomology of a point] Borel and Cartan equivariant cohomology for a compact torus

[Torus classifying-space coefficient ring] Real cohomology of the chosen torus classifying space

[Smooth differential forms] A smooth differential k-form

Facts & Assumptions

Given: AC, the rank-one torus T=R/Z, its trivial action on {∗}, and the degree-two normalization fixed in the A-page definition.

[A1]

Assume the Axiom of Choice, as required by the selected coefficient-ring and Cartan definitions. The Axiom of Choice

[F1]

The Borel construction and Cartan complex use the selected product Milnor model; the Cartan polynomial generators have degree two. Borel and Cartan equivariant cohomology for a compact torus

[F2]

The selected coefficient identification sends the period-one Lie-algebra dual generator to u and gives H∗(BT;R)≅R[u]. Real cohomology of the chosen torus classifying space

[F3]

Smooth differential k-forms are sections of the exterior powers of the cotangent bundle. A smooth differential k-form

Proof

1.1givenA1F1F2

Since the action on the point is trivial, ET×T{∗}=ET/T=BT by the Borel definition [F1]. Its singular cohomology ring is R[u] by [F2].

1.2F1F3given

The tangent and cotangent spaces of a point are zero. Every real-valued function on the singleton is constant, so [F3] gives Ω0({∗})=R; for k>0, the kth exterior power of its zero cotangent space is zero, hence Ωk({∗})=0. Every fundamental field is zero and the exterior derivative of a constant function is zero. Thus the Cartan complex is R[u] with zero differential, whose cohomology ring is R[u].

2.1F2step 1.1step 1.2∎

Both presentations use the degree-two generator fixed in [F2], so the displayed rings agree under that normalization. The example asserts no comparison for other T-manifolds.

Depends on

Dependency tree · 2 levels

Sources