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Quantum occupation fluctuations and the classical approximation boundary

Physical scope

A one-mode exact comparison of Bose, Fermi, and first-order classical occupations at q=1/2, with no empirical interpretation.

Example

Take one dimensionless mode with fugacity q=1/2. The first-order dilute term for the mean occupation is q=1/2. As an explicit comparison, define the Poisson law by Pq(n)=e−qqn/n! for n∈N0; its mean and variance are both q. The exact Bose law is geometric and the exact Fermi law is Bernoulli. This declared calculation illustrates the distinct occupation statistics and why a small-error conclusion needs a small-fugacity condition; the Poisson comparison is not asserted to follow from the linked theorem's mean and log-partition bounds.

Verification

[F1] Controlled dilute Bose/Fermi occupation limit, Statement: Bose and Fermi mode means are q/(1−q) and q/(1+q), with explicit errors relative to q.

[F2] Explicit diagonal Fock domains and occupation trace, Statement: the one-mode Bose and Fermi variances are q/(1−q)2 and q/(1+q)2.

1.1givenF1algebra

Substitution of q=1/2 gives nˉB=1, nˉF=1/3, while the first-order value is 1/2. Thus the Bose error is 1/2 and the Fermi error magnitude is 1/6.

2.1givenF2algebra∎

For the comparison law, EN=e−q∑n≥1nqn/n!=q and E[N(N−1)]=e−q∑n≥2n(n−1)qn/n!=q2, so Var⁡(N)=q2+q−q2=q=1/2. The exact variances from [F2] are q/(1−q)2=2 for bosons and q/(1+q)2=2/9 for fermions. These are finite exact model values; since q is not near zero, no small-error claim follows from this example.

Depends on

Dependency tree · 2 levels

Sources