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One bosonic and one fermionic mode at a specified temperature

Physical scope

An exact hypothetical canonical calculation for one bosonic oscillator mode and one fermionic two-level mode with beta times excitation energy equal to log 2; it is not a measurement or a thermalization claim.

Example

Assume AC and Countable Choice as required by Finite bosonic and fermionic mode partition and occupation formulas. Choose T>0 kelvins and excitation energy ε=kBTlog⁡2 joules, so q=e−βε=1/2. Consider separately one bosonic mode with occupations n=0,1,2,… and one fermionic mode with occupations n=0,1.

Facts & Assumptions

Given: The declared one-mode systems, their positive excitation energy, and the adopted Gibbs preparation.

[F1]

Finite bosonic and fermionic mode partition and occupation formulas: for q=e−βε, the bosonic partition trace is (1−q)−1 with mean q/(1−q), and the fermionic partition sum is 1+q with excited occupation q/(1+q); these are conditional on its stated quantum preparation and suppliers.

[F2]

SI quantities and unit conventions: T is in kelvins, kB in J K−1, and β=(kBT)−1 in J−1.

[A1]

The selected energy is ε=kBTlog⁡2>0 joules, and q=e−βε=1/2.

[A2]

AC and Countable Choice are assumed through [F1] for the quantum Gibbs assignment and the supplied one-mode calculations.

Verification

Given: q=1/2 and the finite-mode identities in [F1].

1.1givenF1F2A1algebra

The bosonic trace is ZB=(1−1/2)−1=2, and the probability of occupation n is 2−(n+1). Its mean occupation is (1/2)/(1−1/2)=1.

2.1F1F2A1algebra∎

The fermionic partition sum is ZF=1+1/2=3/2, so the ground and excited probabilities are 2/3 and 1/3, respectively, and the mean occupation is 1/3. The bosonic and fermionic values belong to distinct declared models.

Depends on

Dependency tree · 2 levels

Sources