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Differentiation of sums, scalar multiples, inner products, cross products and squared norms of differentiable curves in
Statement
Let be an interval with at least two points (Intervals of : the nine order-convex forms, nondegeneracy, and length), let , let be differentiable at (The derivative and the Riemann integral of a vector-valued function: an intrinsic derivative and a componentwise integral) and let be differentiable at (The derivative of at a point that is a limit point of , and differentiability on a set). Write for the derivatives, for the Euclidean inner product and for the Euclidean norm (The Euclidean inner product on ), and for the cross product (The cross product in ). Then:
- and are differentiable at , with and ;
- is differentiable at , with derivative ;
- is differentiable at , with derivative ;
- is differentiable at , with derivative .
Facts & Assumptions
Given: An interval with at least two points, a point , curves and a function , with differentiable at .
A function is differentiable at if and only if every component is differentiable at as a real function on , and then ; moreover sums and scalar multiples of differentiable curves are differentiable with and for (The derivative and the Riemann integral of a vector-valued function: an intrinsic derivative and a componentwise integral).
Sums, scalar multiples and products of real functions differentiable at are differentiable at with the sum, scalar-multiple and product rules (Sums, scalar multiples, products and quotients: , , , and when ); the limit-point hypothesis of that theorem is part of the meaning of differentiability at (The derivative of at a point that is a limit point of , and differentiability on a set, Limit point, isolated point, adherent point, derived set, and dense subset of ).
The Euclidean inner product and norm are and ; the inner product is bilinear and symmetric (The Euclidean inner product on , Laws of finite sums and finite products).
For all the cross product is bilinear-alternating: is bilinear, , and ; in coordinates , , (The cross product in , The cross product is bilinear, alternating, and orthogonal to both factors).
Proof
By [L1] the components are differentiable at with and , and by [L2] each of the functions , , is differentiable at with the sum, scalar-multiple and product rules; this proves clause 1 componentwise, since and .
The scalar function is a finite sum of products of functions differentiable at , hence by [L2] differentiable at with derivative ; by [L3] this is , which is clause 2.
Each component of is, by [L4], one of the differences , , of products of functions differentiable at , so [L2] makes it differentiable at with derivative , and by [L4] and bilinearity this is the corresponding component of ; reassembling the three components with [L1] gives clause 3.
Applying clause 2 at gives differentiability of with derivative , the two terms being equal by symmetry of the inner product [L3]; this is clause 4.
Depends on
The derivative and the Riemann integral of a vector-valued function: an intrinsic derivative and a componentwise integral
The Euclidean inner product on
The cross product in
The derivative of at a point that is a limit point of , and differentiability on a set
Limit point, isolated point, adherent point, derived set, and dense subset of
Intervals of : the nine order-convex forms, nondegeneracy, and length
Sums, scalar multiples, products and quotients: , , , and when
The cross product is bilinear, alternating, and orthogonal to both factors
Laws of finite sums and finite products
Dependency tree · 2 levels
Sources
- Konstantin Likharev, Essential Graduate Physics: Classical Mechanics, §1.3, Eq. (1.32), printed pp. 10-11: the product rule $(\mathbf r\times\mathbf p)'=\mathbf r'\times\mathbf p+\mathbf r\times\mathbf p'$ for angular momentum
- David Tong, Classical Dynamics (University of Cambridge), §§1.2-1.3, printed pp. 2-8: differentiation of $\mathbf p=m\dot{\mathbf r}$, of $\mathbf r\times\mathbf p$ and of the kinetic energy $\frac12\sum_i m_i\dot{\mathbf r}_i^{\,2}$