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Wired FK annuli and the numerical self-dual threshold

Statement

Let q≥1 be real, p∈(0,1), Λn=[−n,n]2∩Z2, and ϕn,p,qb the finite square-lattice FK law with free boundary partition b=0 or wired partition b=1. All paths below use actual open lattice edges, not artificial wiring edges. For each cylinder event A let πp,qb(A)=lim⁡n→∞ϕn,p,qb(A) be its numerical cylinder limit. Put ps=q/(1+q) and let Dr be the cylinder event that 0 connects inside Λr to its vertex boundary. Then an(p,q)=ϕn,p,q1(Dn) decreases, and Θ1(p,q):=lim⁡n→∞an(p,q)=inf⁡r≥1πp,q1(Dr). For p>ps, Θ1(p,q)>0; for p<ps, Θ1(p,q)=0. Consequently inf⁡{p∈(0,1):Θ1(p,q)>0}=ps. No value at ps is asserted. These numerical conclusions do not require Countable Choice or the extension of cylinder weights to an infinite-volume measure.

More precisely, fix p>ps and any real α>1. Put rk=⌊αk⌋. For all sufficiently large k, let Ak be the cylinder event that an actual open simple circuit surrounds Λrk, lies outside Λrk and strictly inside Λrk+1, and is connected inside Λrk+2 to its vertex boundary. There are C,ε>0 and an integer K such that dk=Ce−εk<1/2 for k≥K and, for every n≥m≥N≥K, ϕrn+2,p,q1(⋂k=NmAk)≥∏k=Nn(1−dk),πp,q1(⋂k=NmAk)≥1−∑k=N∞dk. For 0<p<t<1 and Hn the finite Hamming distance to Dn, the finite cylinder expectation satisfies πp,q1(Dn)≤exp⁡{−4(t−p)Eπt,q1Hn}. For every 0<s<ps and every d>0, there are Cd,nd such that πs,q1(Dn)≤Cdn−(2d+4) for n≥nd. The expectation here is a finite sum of cylinder atom weights.

Facts & Assumptions

Given: The finite FK laws for real q≥1, their deterministic cylinder limits, and the finite torus RSW and influence interfaces in the cited suppliers.

[F1]

Finite FK is positively associated, has the spatial Markov property, is increasing in parameter and boundary wiring, and has conditional edge-open probability at least ρ=p/[p+q(1−p)] (Finite FK association, spatial Markov property, and boundary monotonicity).

[F2]

Numerical free/wired cylinder limits exist, are translation and quarter-turn invariant, obey parameter and boundary comparison, and agree outside an at most countable parameter set Jq (Numerical FK cylinder limits and pressure comparison). These are numerical identities, not an assumed Borel extension.

[F3]

Every fixed-aspect rectangle strictly inside a periodic torus has a uniform positive self-dual crossing probability (Periodic-torus RSW lower bounds at the FK self-dual point).

[F4]

The finite conditional-influence bound is that of A maximum conditional edge influence bound for finite FK measures.

[F5]

Complement-edge planar duality has parameter p∗/(1−p∗)=q(1−p)/p and includes the exterior-face convention (Planar FK duality with the free exterior-face convention).

[F6]

Opposite-direction grid crossings intersect, and simple polygonal circuits separate their bounded and unbounded components (Opposite crossings of a rectangular grid intersect, Polygonal Jordan curve theorem: a polygon has exactly two complementary regions and is the frontier of each).

Proof

1.1F1F4algebra

For an increasing event B on a finite graph, differentiation of its finite FK weights gives ϕp′(B)=Cov⁡p(1B,∣ω∣)/[p(1−p)]. Writing ue=ϕp(e open) and IB(e)=ϕp(B∣e open)−ϕp(B∣e closed) yields ϕp′(B)=∑eue(1−ue)IB(e)/[p(1−p)]. By [F1] the coefficients have a positive lower bound on a compact parameter interval inside (0,1). On an L-torus a translation-invariant B has equal influences on each of the two edge orbits, each of size L2. Thus [F4] implies ϕp′(B)≥cϕp(B)(1−ϕp(B))log⁡L. Integrating its logistic derivative between ps and fixed p>ps shows that ϕps(B)≥b>0 implies 1−ϕp(B)≤CL−η, with constants independent of L.

1.2F6construct

We specify the finite stopping operation used for an outer circuit. In a finite ambient box list all simple circuits disjoint from Λrk+1, strictly inside Λrk+2, and surrounding the inner square. For a candidate γ, let I(γ) be the edges whose relative interiors lie in its bounded component, including edges entering that component from circuit vertices. Let O(γ) contain all other ambient edges, including circuit edges. The event selecting Γ=γ is: every edge of γ is open and there is no surrounding open circuit in O(γ) whose bounded interior strictly contains that of γ. These tests involve only O(γ). To verify that exactly one candidate is selected whenever a surrounding circuit exists, splice any exterior excursion of another surrounding circuit with the outer arcs of γ, keeping the unbounded face on the outside, and erase subloops not surrounding the inner square. This gives a surrounding circuit in the union, on or outside γ, with strictly larger interior if that excursion protrudes. Applying this finite operation to all candidates yields an outermost circuit; two different maximal circuits would enlarge each other by the same surgery. Equal interiors have the same Jordan boundary. Thus the selected candidate is unique. For each output (γ,τ), where τ is the full assignment on O(γ), the output fiber is precisely the fixed-exterior cylinder {ω∣O(γ)=τ} if τ passes the tests, and is empty otherwise. Every interior assignment is admitted. This fiber identity, rather than a claim about a particular probing order, certifies that conditioning on the output never conditions an interior edge.

1.3F1F2algebra

For m≥r, reaching ∂Λm entails Dr, and wired domain comparison gives am≤ϕm,p,q1(Dr)≤ar. In particular an decreases, so Θ1=inf⁡nan exists. Taking m→∞ in the displayed inequalities gives Θ1≤πp,q1(Dr)≤ar. Infimizing over r proves Θ1=inf⁡rπp,q1(Dr). This is a pair of real inequalities, not an exchange of two limits.

1.4F1F2algebra

On a finite edge set and for an increasing event D, its Hamming distance HD is the minimum number of closed edges to open to enter D. Opening one coordinate lowers it by zero or one; hence ∣ω∣+HD is increasing, HD is decreasing, and HD1D=0. Finite differentiation and FKG give ddpϕp(D)={Cov⁡p(1D,∣ω∣+HD)+ϕp(D)EpHD}/[p(1−p)]≥4ϕp(D)EpHD. Integrate from p to t>p and use monotonicity of the decreasing HD to obtain ϕp(D)≤exp⁡{−4(t−p)EtHD}. Apply this to Dn in wired Λm with m>n and take m→∞. Both sides involve only fixed finite cylinder sums, proving the claimed Hamming inequality.

1.5F1F2F5constructalgebra

We derive the exact numerical free/wired duality from a concrete free plane graph. Let Hm be the free rectangular grid on the (2m)2 unit-cell centers of Λm. Each bounded face of Hm surrounds one interior vertex of Λm; its one unbounded face represents all vertices of Bm identified together. A dual edge of Hm crosses exactly one nonperimeter edge of Λm, with precisely those interior-vertex or boundary-class endpoints. Thus Hm∗ is the wired quotient graph with the perimeter edge labels omitted. Each omitted perimeter edge is a loop after wiring, so its open/closed weight sums to p+(1−p)=1 independently and changes no retained-edge law. Apply [F5] to the connected free plane graph Hm at parameter t∗, whose dual parameter is t. The inverse complement bijection sends the wired retained-edge law at t to the free law on Hm at t∗. This proves the finite identity before taking any limit; the exterior face is one of the wired-quotient vertices, not an additional cell-center vertex. The cell-center grids exhaust the translated dual lattice, and, after its fixed half-unit identification with Z2, lie between centered boxes with radii differing by a fixed constant. Finite domain comparison and [F2] therefore give, for every dual cylinder E, πt,q1(dual-complement E)=πt∗,q0(E). This is a numerical cylinder identity, not a claim of an unconstructed infinite law.

2.1F1F3F6step 1.1construct

To turn this estimate into a bound for one specified rectangle, first take width 2u, height 2bu with integer b≥1, and torus side L=16b2u. Let B mean that some translate of a width-u, height-L/2 rectangle has a vertical crossing. It is translation invariant and has self-dual probability bounded below by [F3], since its fixed aspect is 8b2 and its height is strictly less than L. Every such narrow strip is contained horizontally in one of the width-2u strips starting on the u-grid, and its height interval contains a full height-2bu band starting on the 2bu-grid. Its crossing therefore crosses one of M=(L/u)(L/(2bu)) fixed translates of the target rectangle. Wrapping translates are lifted to the plane for this containment. If their crossing events are Bi, positive association of their decreasing complements gives (1−ϕp(B1))M≤ϕp(⋂iBic)≤ϕp(Bc). Step 1.1 proves ϕp(B1)≥1−Cu−η/M. The number M is independent of u.

3.1F1step 2.1constructalgebra

For a rectangle of width w and height h with 1≤h/w≤β, take u=⌊w/2⌋ and a fixed integer b depending only on β with 2bu≥h. A crossing of the narrower, taller rectangle restricts to a crossing of the target. Rotating handles the other orientations. A fixed enlargement of L/u in step 2.1 preserves the proof and accommodates any surrounding planar box of size comparable to w. Condition that torus law on all edges outside the box; its induced partition is bounded above by the wired partition. Hence the wired box gives the specified rectangle a crossing probability at least 1−Cw−δ. The finitely many small widths are absorbed into C.

4.1F6step 3.1constructalgebra

Fix α>1. For large k put a=rk+2, b=rk+1−2, R=rk+2. Use vertical crossings of [a,b]×[−b,b] and [−b,−a]×[−b,b], horizontal crossings of [−b,b]×[a,b] and [−b,b]×[−b,−a], and a horizontal crossing of [−R,R]×[−b,b]. In each corner square the adjacent side crossings intersect by [F6]; their union contains a surrounding closed walk, from which erasing nonsurrounding loops gives a simple circuit. The last crossing intersects the two vertical sides and connects that circuit to the outer boundary. All widths are comparable to αk and all aspects are fixed. Step 3.1 and a union bound give ϕrk+2,p,q1(Ak)≥1−dk with dk=Ce−εk. Enlarge K until b>a and dk<1/2 for k≥K.

5.1F1F6step 4.1step 1.2construct

Suppose Ak+1,…,An hold. Apply step 1.2 to the next annulus. The selected Γ has an outgoing open connection to ∂Λrk+3: an outgoing path from any surrounding circuit meets Γ. These outer events are measurable in its returned exterior data. For Ak+1 one may use Γ itself, and any path excursion inside it can be replaced by an open circuit arc; circuits of Aj for j≥k+2 are outside it. On each output fiber, [F1] gives the interior FK law with all vertices of Γ wired together by its actual open edges. Let Gk(Γ) mean that a circuit of the inner annulus connects to Γ inside its bounded domain. In wired Λrk+2, Ak implies Gk(Γ) by separation, even when the fixed geometric Γ is not open in that comparison law. Wired FK inside Γ dominates the restriction of wired FK on the larger square. Step 4.1 therefore gives conditional probability at least 1−dk for Gk(Γ). Its connection then follows the already exposed outgoing path through Γ to ∂Λrk+2, giving Ak. Averaging the exterior fibers proves P(Ak∣Ak+1,…,An)≥1−dk. No square boundary is asserted to be wired in the random configuration.

6.1F2step 4.1step 5.1algebra

Start in wired Λrn+2, where An has probability at least 1−dn, and descend using step 5.1. This proves the finite product bound for ⋂k=NnAk, and hence for ⋂k=NmAk. For fixed m, take the deterministic outer-box limit along n→∞; finite additivity and ∏k=Nn(1−dk)≥1−∑k=Nndk prove the stated cylinder lower bound. No probability of an infinite intersection or measure extension is used.

7.1F1F2F6step 6.1step 1.3construct

For p>ps choose N≥K with ∑k≥Ndk≤1/2. Fix a deterministic nearest-neighbor tree containing all vertices of ΛrN+1; if it has M0 edges, its all-open event T has probability at least ρM0 by successive edge conditioning. Finite FKG and step 6.1 give ϕrn+2,p,q1(T∩⋂k=NmAk)≥ρM0/2 for n≥m≥N. Consecutive circuits connect because an outgoing path meets the next surrounding circuit. For any prescribed R, take the least m≥N with rm+2>R; this finite chain and the tree imply DR. Taking only the outer-box limit gives πp,q1(DR)≥ρM0/2 for every R, with the same constant. Step 1.3 proves Θ1(p,q)>0.

7.2F2step 6.1step 1.5construct

Fix 0<s<ps and choose one t∈(s,ps) such that t∗∉Jq. The preimage of Jq under the explicit dual bijection is countable. A point outside it can be specified without Countable Choice: enumerate that exceptional set, start with a rational closed interval inside (s,ps), and recursively take the first smaller rational closed interval in a fixed enumeration which avoids the next exceptional point and has diameter at most half the previous diameter. Its unique limit lies outside the exceptional set. Since t∗>ps, step 6.1 at the dual parameter, for any chosen α>1, supplies N such that every finite intersection of dual annulus events with indices from N onward has numerical wired weight at least 1/2. By equality of the free/wired cylinder weights at t∗ and step 1.5, the same finite dual-circuit intersections have primal wired cylinder weight at least 1/2 at t.

8.1F6step 1.3step 1.4step 7.2algebra

Retain every other annulus, so its dual circuits have disjoint edge supports. Among the annuli strictly inside Λn−2 there are at least (log⁡n)/(2log⁡α)−O(N+1) retained circuits; the fixed dual-lattice translation changes only the cutoff. Every primal path realizing Dn must cross each such circuit at a distinct closed primal edge. On the finite cylinder supporting these circuits and Hn, multiply this pointwise inequality by its nonnegative atom weights and sum. Step 7.2 gives Eπt,q1Hn≥(log⁡n)/(8log⁡α) for large n. Taking log⁡α=(t−s)/(4d+8) in step 1.4 gives πs,q1(Dn)≤n−(2d+4) for sufficiently large n, proving the claimed bound after enlarging Cd. In particular these probabilities tend to zero, so step 1.3 yields Θ1(s,q)=0. All intersections and expectations used here are finite.

9.1step 7.1step 8.1algebra∎

Every parameter strictly above ps belongs to the set defining the numerical threshold by step 7.1, and none strictly below belongs by step 8.1. Its infimum is therefore ps. The proof never assigns a value at ps and never invokes an infinite-volume probability measure or Countable Choice.

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