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Weak Dirichlet problem with prescribed fractional Sobolev boundary data

Statement

Assume the Axiom of Choice and Countable Choice as declared by the trace and Sobolev suppliers (The Axiom of Choice). Let Ω⊂R3 be a bounded C1 domain, let ε be a measurable symmetric uniformly elliptic coefficient as in the lift lemma (Weak Dirichlet existence for a prescribed lift and uniformly elliptic coefficient), let ρ∈L2(Ω), and prescribe g∈H1/2(∂Ω)=W1/2,2(∂Ω), the fractional Sobolev space of the boundary definition, defined by a finite graph atlas and partition with norm given by the finite sums of localised L2 norms and Gagliardo seminorms (The fractional Sobolev space on a compact C1 boundary, The Lp trace operator on a bounded C1 domain). Then there is exactly one u∈H1(Ω) with trace Tu=g solving

∫Ω∇v⋅ε∇u=∫Ωρ vfor every v∈H01(Ω),

and the solution depends continuously on (ρ,g): ∥u∥H1≤C(∥ρ∥L2+∥g∥H1/2). The prescribed trace is exact and no classical C2 boundary regularity is inferred.

Facts & Assumptions

Given: A bounded C1 domain Ω⊆(−L,L)3 with trace operator T, a uniformly elliptic coefficient ε with constants 0<α≤β<∞, data ρ∈L2(Ω) and g∈H1/2(∂Ω), and the weak equation of the Statement.

[F1]

Sharp trace and bounded right inverse. Under the Axiom of Choice, T:W1,2(Ω)→W1/2,2(∂Ω) is bounded and onto (The sharp trace theorem: boundedness and range in the fractional space), and there is a bounded linear right inverse R:H1/2(∂Ω)→H1(Ω) with TRg=g and ∥Rg∥H1≤C∥g∥H1/2 (A bounded right inverse of the trace, supported in a prescribed collar); the fractional space is defined by the finite chart/Gagliardo construction (The fractional Sobolev space on a compact C1 boundary).

[F2]

Trace kernel. {u∈W1,2(Ω):Tu=0}=H01(Ω) (The kernel of the trace is the closure of the test functions, The Axiom of Choice).

[F3]

Lift existence and integral bound. For every specified lift G∈H1(Ω) and bounded F on H01, there is a unique u∈G+H01 with ∫∇v⋅ε∇u=F(v) for all v∈H01 (Weak Dirichlet existence for a prescribed lift and uniformly elliptic coefficient). Cauchy-Schwarz gives ∣∫fg∣≤∥f∥2∥g∥2 (Cauchy-Schwarz inequality for L2). For the positive symmetric pointwise form bx(ξ,η)=ξ⋅ε(x)η, nonnegativity of bx(ξ+tη,ξ+tη) for all t∈R gives ∣bx(ξ,η)∣≤β∣ξ∣∣η∣. Thus ∣a(G,v)∣≤β∥∇G∥2∥∇v∥2.

[F4]

Zero-boundary coercivity. Under AC and Ω⊆(−L,L)3, H01 is a complete Hilbert space, ∥v∥2≤2L∥∇v∥2 and ∥∇v∥2≤∥v∥H1≤1+(2L)2∥∇v∥2 for v∈H01 (The gradient norm dominates the H-one norm on zero-boundary Sobolev space). In particular ∣∫ρv∣≤2L∥ρ∥2∥∇v∥2 by [F3].

Proof

technique · direct
1.1givenF1algebra

By [F1] choose the bounded right inverse R and put G=Rg∈H1(Ω); then TG=T(Rg)=g, so G is an exact H1 lift of the prescribed fractional datum.

2.1step 1.1F2algebra

A function u∈H1(Ω) satisfies Tu=g exactly when u−G∈H01(Ω): indeed T(u−G)=g−g=0 is equivalent to u−G∈H01 by [F2].

3.1step 1.1step 2.1F3F4algebra

Apply the lift existence theorem [F3] with the specified lift G=Rg and the functional F(v)=∫ρv: there is a unique u=G+w, w∈H01, with ∫∇v⋅ε∇u=F(v) for every v∈H01; by step 2.1 its trace is exactly g, and uniqueness of w gives uniqueness of u among H1 functions with trace g solving the equation.

4.1step 3.1F1F3F4algebra

Continuous dependence: for two data sets (ρi,gi), i=1,2, put Gi=Rgi and wi=ui−Gi; subtracting the weak equations and testing with v=w1−w2 gives α∥∇(w1−w2)∥22≤(2L∥ρ1−ρ2∥2+β∥∇R(g1−g2)∥2)∥∇(w1−w2)∥2 by [F3] and [F4], hence ∥∇(w1−w2)∥2≤α−1(2L∥ρ1−ρ2∥2+β∥∇R(g1−g2)∥2); adding ∥R(g1−g2)∥H1≤C∥g1−g2∥H1/2 by [F1] and using the equivalence of the gradient and full norms on H01 [F4] yields the stated bound ∥u∥H1≤C(∥ρ∥2+∥g∥H1/2) with the case (ρ2,g2)=(0,0).

5.1step 3.1step 4.1F1algebra∎

The prescribed trace is membership in the affine class G+H01 and its identification Tu=g through the bounded trace operator [F1], not a classical C2 boundary regularity statement; this proves existence, exactness of the trace, uniqueness and continuous dependence.

Depends on

Dependency tree · 2 levels

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