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Gauss charge and finite-chain flux balance

Statement

Let (M,g,N,o) be the smooth oriented and time-oriented Lorentzian four-manifold of Oriented Lorentzian fields, observers and coordinate conventions, let F∈Ω2(M) and j∈Γ(TM) be smooth, and fix constants c,μ0>0. Assume dF=0 and ∇aFab=−μ0jb, equivalently d(⋆gF)=μ0ιjvolg by Sourced Maxwell sign and current conservation. A finite smooth singular k-chain means a finite formal real linear combination of smooth singular k-simplices, with the boundary operation of The metric volume form, current flux through 3-faces and finite-chain charges and Stokes theorem for smooth singular chains.

For a finite smooth singular three-chain Σ, define its charge by

Q(Σ):=1c∫Σιjvolg.

Then:

(a) Gauss charge formula. For every such Σ,

Q(Σ)=1μ0c∫∂Σ⋆gF.

Consequently, if ∂Σ=0, then Q(Σ)=0. This is the compact-cycle neutrality constraint for a smooth everywhere-defined sourced field.

(b) Bounding-surface restriction. For every finite smooth singular three-chain V, the magnetic flux through its boundary vanishes:

∫∂VF=0.

The equation dF=0 does not imply that the flux through every closed two-cycle is zero; this item gives a zero-flux conclusion only when the cycle is the boundary of a finite smooth chain in the field domain. Likewise, the electric flux formula in (a) identifies charge with flux only for a bounding surface.

(c) Charge balance. If a finite smooth singular four-chain C satisfies ∂C=Σ2−Σ1+B for three-chains Σ1,Σ2,B, then

Q(Σ2)−Q(Σ1)=−Q(B).

Equal charge on the two slices therefore requires zero net side flux. No asymptotic charge or flux at infinity is asserted; noncompact limits require separate convergence and boundary-flux hypotheses.

Facts & Assumptions

Given: A smooth oriented Lorentzian four-manifold, smooth F and j, positive constants c,μ0, the two Maxwell equations in the Statement, and finite smooth singular chains of the indicated degrees.

[F1]

Sourced Maxwell sign and current conservation proves d(⋆gF)=μ0ιjvolg and ∇aja=0 from the displayed sourced equation. These are conditional mathematical consequences of the specified equation.

[F2]

A smooth singular k-simplex extends smoothly to a neighbourhood of the standard simplex, chains are finite formal sums with signed face boundary, and for every such chain c and smooth form ω, ∫cdω=∫∂cω (The metric volume form, current flux through 3-faces and finite-chain charges, Stokes theorem for smooth singular chains).

[F3]

The flux of a smooth current j through a three-chain is Φj(Σ)=∫Σιjvolg and for a finite four-chain C, Φj(∂C)=∫C(∇aja)volg (The metric volume form, current flux through 3-faces and finite-chain charges, Divergence, Stokes flux balance and the non-null face formula for a Lorentzian current).

[F4]

The inherited smooth tangent-bundle conventions use ACω, whose exact statement is that every countable family of nonempty sets has a choice function (The Axiom of Countable Choice (ACω)). The finite chain and integration arguments add no further choice.

[A1]

The equations dF=0 and ∇aFab=−μ0jb are hypotheses on the entire chain domain. F,j are smooth there; no distributional, punctured-source, limiting-at- infinity or empirical premise is assumed.

Proof

Given: [F1]–[F4] and [A1].

1.1F1F2F4givenalgebra

By [F1], d(⋆gF)=μ0ιjvolg. Integrate this three-form over the finite smooth singular three-chain Σ. By [F2], ∫Σd(⋆gF)=∫∂Σ⋆gF, so μ0∫Σιjvolg=∫∂Σ⋆gF. Divide by μ0c>0 and use the definition of Q to obtain (a)'s formula. The chain Σ was fixed arbitrarily, and no family of chains is selected, as [F4] records.

1.2givenF2A1algebra

Let V be a finite smooth singular three-chain. Apply [F2] to the two-form F on V and use [A1]: ∫∂VF=∫VdF=0. This proves (b) for bounding surfaces; the argument supplies no primitive or flux statement for a nonbounding cycle.

2.1givenstep 1.1F2algebra

If ∂Σ=0, the right side of step 1.1 is the integral over the zero two-chain, which is zero by finite additivity in [F2]. Hence Q(Σ)=0. This conclusion uses a cycle, not merely a closed surface whose homology class is unspecified.

3.1givenF1F3algebra∎

For the four-chain C, [F1] gives ∇aja=0 throughout its domain. By [F3], Φj(∂C)=∫C(∇aja)volg=0. Additivity of the finite-chain integral and ∂C=Σ2−Σ1+B give Φj(Σ2)−Φj(Σ1)+Φj(B)=0. Divide by c>0 and apply the definition of Q to obtain (c). The proof integrates only finite smooth chains, so no boundary-at-infinity term is present.

Remarks

The finite-chain hypotheses are essential to the stated argument. On a noncompact spatial domain, charge conservation requires specified convergence of slice integrals and an explicit treatment of limiting side flux; neither follows from the local differential equation alone.

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