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No-slip compactness and bounded-mode tails

Statement

Assume the Axiom of Choice. Let Ω⊂R3 be bounded and open, and let H,V and (ej)j≥1 be as in the bounded closure-space and basis results on this page. The inclusion V↪H is compact. If ΠK is the H-orthogonal projection onto span⁡(e1,…,eK), then there are numbers δK↓0 such that ∥(I−ΠK)a∥H≤δK∥a∥V(a∈V).

Facts & Assumptions

Given: The Axiom of Choice, a bounded open Ω⊂R3, the spaces H,V and basis (ej) above, and the zero-extension convention.

[A1]

The Axiom of Choice and The Axiom of Countable Choice (ACω): the Axiom of Choice implies Countable Choice, supplying the choice hypothesis required by the zero-extension and L1 fundamental-theorem suppliers below.

[F1]

Bounded no-slip solenoidal closure spaces: V is the closure of Dσ in H01 and its norm controls ∥∇a∥2.

[F2]

Countable smooth solenoidal basis for bounded closure spaces: under the Axiom of Choice, H is complete, (ej) is an H-orthonormal basis, and its finite span is dense in V.

[F3]

Zero extension of W_0^{1,p} has no boundary derivative: under Countable Choice, zero extension preserves the L2 and gradient norms for H01 fields.

[F4]

Fubini's theorem for L^1 functions on a sigma-finite product: integrals over space and the compact mollifier variable may be interchanged for the integrable functions below.

[F5]

The indefinite integral of an L1 function is differentiable almost everywhere: under Countable Choice, the indefinite integral of an L1 function has derivative equal to its integrand almost everywhere. The smooth endpoint identity needed below is derived directly in step 1.1.

[F6]

Holder's inequality for integrals, including the endpoint cases: Cauchy–Schwarz applies to the spatial integrals, segment parameter, and mollifier probability density used below.

Proof

1.1givenA1F1F3F4F5F6algebra

For a real C1 function g on a compact interval [a,b], put G(t)=∫atg′(s)ds. Continuity of g′ gives ∣[G(t+h)−G(t)]/h−g′(t)∣≤sup⁡∣s−t∣≤∣h∣∣g′(s)−g′(t)∣→0 at interior points. Thus (G−g)′=0 everywhere inside the interval, and the mean value theorem and continuity at the endpoints give g(b)−g(a)=∫abg′. Apply this identity to g(s)=w(x−sh), 0≤s≤1, componentwise for vector fields. For w∈Cc∞(R3), [F6] in the segment parameter then gives ∣w(x−h)−w(x)∣2≤∣h∣2∫01∣∇w(x−sh)∣2ds. Integrating in x, using translation invariance and [F4], yields ∥w(⋅−h)−w∥2≤∣h∣∥∇w∥2. Density and the isometric zero extension [F3] extend this estimate to every a∈V.

2.1givenA1F3F4F6step 1.1

Fix a nonnegative η∈Cc∞(R3) with integral one and set ηϵ(x)=ϵ−3η(x/ϵ). For each x, Cauchy–Schwarz with respect to the probability density ηϵ(h) gives ∣∫ηϵ(h)(E0a(x)−E0a(x−h))dh∣2≤∫ηϵ(h)∣E0a(x)−E0a(x−h)∣2dh. Integrating in x, applying [F4] to interchange the integrals, and using step 1.1 give ∥E0a−ηϵ∗E0a∥22≤∫ηϵ(h)∥E0a(⋅−h)−E0a∥22dh≤Cη2ϵ2∥∇a∥22. For the V unit ball this error is uniform and tends to zero with ϵ.

3.1givenA1F2F6step 2.1algebra

For fixed ϵ, all mollified zero extensions have support in one compact box. [F6] bounds their sup norms by ∥ηϵ∥2∥a∥2 and their first derivatives by ∥∇ηϵ∥2∥a∥2, uniformly on the V unit ball. Cover the box by a finite grid fine enough that the derivative bound changes every value by less than a prescribed tolerance; quantize the bounded vector values at grid points in a finite lattice. The resulting finitely many piecewise-constant fields approximate every mollified field in sup norm, hence in L2 on the finite box. Step 2.1 transfers these finite nets to finite L2 nets for the original V unit ball, with arbitrarily small error. Thus that ball is totally bounded in H; completeness of H from [F2] makes its closure compact.

4.1givenF2step 3.1∎

For every a in that compact closure, ΠKa→a in H by the H-basis property in [F2]. Given ϵ>0, take a finite ϵ-net of the compact set and choose K so that ∥(I−ΠK)b∥<ϵ at each net point b. Since I−ΠK is an orthogonal contraction, the triangle inequality gives sup⁡∥a∥V≤1∥(I−ΠK)a∥≤2ϵ. These suprema decrease with K; taking them as δK proves δK→0 and, by homogeneity, the asserted estimate.

Depends on

Dependency tree · 2 levels

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