Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedverified 2026-10-23 (gpt-6.1-sol)
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Transport across a moving control boundary

Statement

Assume countable choice: every countable family of nonempty sets has a choice function. Let I⊆R be an open interval, let C0⊆R3 be a bounded open region with C1 boundary (locally a C1 graph with the region on one side), and let UC be an open neighborhood of C0‾. Let X∈C2(I×UC;R3) have orientation-preserving diffeomorphic time slices onto open images (bijections with C2 inverses and positive Jacobian determinant). Here Cr means all coordinate partial derivatives through order r are continuous, and set C(t)=Xt(C0). Let g be a scalar C1 field on an open neighborhood of {(t,x):x∈C(t)‾, t∈I}. Define the boundary velocity by w(t,X(t,ξ))=∂tX(t,ξ) and let n be the outward Euclidean unit normal on ∂C(t). Use Euclidean surface measure, whose chart density is det⁡(DYTDY). Then ddt∫C(t)g(t,x) dx=∫C(t)∂tg(t,x) dx+∫∂C(t)g(t,x) w(t,x)⋅n(t,x) dSx. For vector-valued g, the identity holds componentwise. No condition equating w with a fluid velocity is required.

Facts & Assumptions

Given: Countable choice, the stated C2 family of orientation-preserving diffeomorphisms, bounded C1 reference region, and scalar field defined near the swept closures.

[A1]

The Axiom of Countable Choice (ACω): countable choice means that every countable family of nonempty sets admits a choice function.

[F1]

C1 material regions have compatible Jordan volume integrals: a bounded open C1 region and its compact closure have matching integrals for continuous fields; its compact closure is Jordan measurable.

[F2]

Smooth transport, Jacobian and advected reference density: for a compact Jordan reference set and a C1 scalar field, differentiation of the integral under a C2 orientation-preserving motion gives ∫C(t)(∂tg+div⁡x(gw)) dx.

[F3]

Divergence on a bounded C1 Euclidean domain: under countable choice, a bounded C1 domain and a vector field that is C1 on its closure satisfy ∫Cdiv⁡F dx=∫∂CF⋅n dS.

Proof

1.1givenF1F2algebra

If C0=∅, then C(t)=∂C(t)=∅ for every t, all integrals are zero, and the asserted identity holds without applying the divergence theorem. Henceforth suppose C0≠∅. Fix t0∈I and put K=C0‾. By [F1], K is compact Jordan and integration over C(t0) agrees with integration over Xt0(K). Translate time by t0 and apply [F2] to the translated motion and field. Since the Eulerian velocity of that motion is w, the derivative at t0 is ∫C(t0)(∂tg+div⁡x(gw)) dx. The argument applies to every t0∈I.

2.1givenA1F3step 1.1∎

The field gw is C1 on a neighborhood of C(t0)‾. Apply [F3] and use ∫Cdiv⁡(gw)=∫∂Cgw⋅n to obtain the stated formula. Apply this scalar argument to each component when g is vector-valued.

Depends on

Dependency tree · 2 levels

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