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Exact quasistatic and finite-interval mass-change bounds
Statement
Assume as defined by The Axiom of Countable Choice (). Let be the relevant constants and initial/cutoff data of Exact ideal emitter mass ODE and entropy accounting, with and . Let
be the positive solution and cutoff supplied by that proposition. Use the diagnostic of Quasistatic diagnostic for the ideal emitter model. Then
For any , the condition therefore implies throughout .
There is also an exact finite-interval bound. If and
then
Both bounds are exact internal consequences of the adopted ODE. They give no error bound between that ODE and an unconstructed Einstein–quantum backreaction solution.
Facts & Assumptions
Given: , the fixed-reference ODE, its positive solution, the cutoff and constants of Exact ideal emitter mass ODE and entropy accounting, with , , and .
The Axiom of Countable Choice (): means every countable family of nonempty sets has a choice function; this is the exact choice assumption carried by the mathematical photon-flux supplier.
Exact ideal emitter mass ODE and entropy accounting: its Statement defines , , and the exact positive solution until .
Quasistatic diagnostic for the ideal emitter model: and ; the latter is a dimensionless ODE diagnostic only.
The mean value theorem, as the case of Cauchy's: for continuous on with and differentiable on there is with : if a function is continuous on a closed interval and differentiable in its interior, its endpoint difference equals its derivative at an interior point times the interval length.
Proof
Given: A positive solution of the stated ODE on , positive , and the definitions in [F1]–[F2].
Differentiate the exact solution in [F1] on ; since , this gives . Also [F1] gives , so substituting these identities and into [F2] yields
All factors are positive on the interval.
From [F1], . Divide by the positive and take positive cube roots to get .
Since , one has . The formula in step 1.1 gives the uniform upper bound; if , multiplying by the positive denominator yields .
If , step 1.2 gives a ratio of one and the bound is equality. If , is continuous on , differentiable on its interior, and satisfies . Apply [F3] on this nondegenerate interval and use to obtain . Step 1.2 gives the claimed ratio bound.