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Third Stiefel–Whitney Classes of Tangent and Normal Bundles

Statement

Let X be a paracompact Hausdorff compactly generated weak Hausdorff space of CW homotopy type, and let E,F→X be numerable finite-rank real vector bundles. Assume full AC as required by the imported characteristic-class and Bockstein suppliers. If

w1(E)=w1(F)=0,w2(E⊕F)=0

in mod-two singular cohomology, then

W3(E)=W3(F)and2W3(E)=0

in H3(X;Z). In particular, the equality applies to an oriented tangent bundle and its oriented normal bundle when their direct sum has vanishing w2.

Facts & Assumptions

Given: Full AC; numerable finite-rank real bundles E,F→X over the stated base, with w1(E)=w1(F)=0 and w2(E⊕F)=0.

[F1]

Stiefel–Whitney classes from the projective-bundle relation: wj(G)∈Hj(X;Z/2) are the Stiefel–Whitney classes of a numerable finite-rank real bundle G.

[F2]

Whitney sum formula for Stiefel–Whitney classes: w(E⊕F)=w(E)⌣w(F).

[F3]

Integral Third Stiefel–Whitney Class and Bockstein connecting operation: W3(G)=β~2(w2(G)), with β~2 the integral connecting operation for 0→Z→×2Z→Z/2→0.

[F4]

Bockstein connecting operation and Singular cohomology with coefficients: the connecting homomorphism is computed by lifting a mod-two singular cocycle to an integral cochain and dividing its integral coboundary by 2.

[F5]

The Bockstein is independent of lift and representative: this operation gives a well-defined cohomology class, independent of the cochain lift and cocycle representative.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function; this is the full choice hypothesis of the imported Bockstein and characteristic-class suppliers.

Proof

1.1givenF1F2A1algebra

The degree-two part of [F2] gives w2(E⊕F)=w2(E)+w1(E)⌣w1(F)+w2(F). The two degree-one classes vanish by the Given clause, and the left side vanishes by the Given clause, so w2(E)+w2(F)=0. Since these classes have coefficients in Z/2, this says w2(E)=w2(F).

2.1F3F5A1step 1.1algebra

Apply the well-defined operation β~2 to the equality in step 1.1 and use [F3]. This gives W3(E)=W3(F).

3.1givenF3F4F5A1algebra∎

Represent w2(E) by a mod-two singular 2-cocycle c. Lift each value of c to its unique representative 0 or 1, obtaining an integral 2-cochain c~. Because c is a cocycle, every value of δc~ is even, so d=(δc~)/2 is an integral 3-cochain. By [F4] and the lift-independence in [F5], W3(E)=[d]. Therefore 2W3(E)=[2d]=[δc~]=0, since δc~ is a coboundary.

Remarks

The equality uses the integral Bockstein, so torsion is retained. The proof does not assume a classification theorem for spin structures; its input is the explicit vanishing of w2(E⊕F).

Depends on

Dependency tree · 2 levels

Sources