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Mass shell, observer energy and inertial work

Physical scope

Conditional constant-mass mass-shell and observer-decomposition identities; coordinate work relation only in flat inertial charts; variable-mass formula is kinematic only.

Statement

For a massive body with constant m>0, P=mU, g(U,U)=−c2, and the force law of Prescribed constant-mass force law,

g(P,P)=−m2c2.

For every observer n at the event, the energy and spatial momentum defined in Mechanical momentum and observer energy satisfy

En(P)2=m2c4+c2g(qn(P),qn(P)),En(P)>0.

For a nonzero future-null P, En(P)=cg(qn(P),qn(P)). In a flat inertial frame (o;e0,e1,e2,e3) with n=e0 and inertial chart x0=ct from Inertial frames and inertial charts of the affine Minkowski model, let E=En(P), let p be the spatial coordinates of qn(P) in (e1,e2,e3), set v=dx/dt, and define F=dp/dt. Then dE/dt=F⋅v under the constant-mass force hypotheses. If m(τ)>0 is C1, U is C1 with g(U,U)=−c2, and P=m(τ)U, then the kinematic identity g(U,DτP)=−c2m˙ holds; it specifies no variable-mass law.

Facts & Assumptions

Given: A future unit timelike tangent U, constant m>0 on the massive branch, an observer n, and the force assumptions of the Statement.

[F1]

The prescribed force is orthogonal to U and the local IVP preserves g(U,U)=−c2 (Prescribed constant-mass force law, Smooth shell-tangent force initial-value problem).

[F2]

For an observer, qn(P)=P+g(P,n)n and g(qn(P),qn(P))=g(P,P)+g(P,n)2 (Mechanical momentum and observer energy, The observer rest-space decomposition and the spatial projection).

[F3]

Pairing a future timelike vector with a future observer is strictly negative (Pairing of an observer with future causal vectors).

[F4]

In a flat inertial chart with constant mass, the four-force work identity gives dE/dt=F⋅v (Four-force identities and the work-energy relation in an inertial frame).

[F5]

Along a curve, ddτg(V,W)=g(DτV,W)+g(V,DτW) (Covariant differentiation along curves: metric pairing, parallel transport and geodesic speed).

Proof

1.1givenF2algebra

From P=mU and g(U,U)=−c2, g(P,P)=m2g(U,U)=−m2c2. Write a=−g(P,n) and q=qn(P); then P=an+q, g(q,n)=0, and [F2] gives g(q,q)=g(P,P)+g(P,n)2. Since En=ca, rearrangement yields En2=m2c4+c2g(q,q).

1.2F2F3algebra

The vectors P and n are future timelike, so [F3] gives g(P,n)<0 and therefore En=−cg(P,n)>0. For null P, since g(P,P)=0, [F2] yields g(q,q)=g(P,n)2, and positivity selects En=cg(q,q).

2.1givenF1F4F5algebra∎

Under the flat inertial constant-mass hypotheses, [F1] identifies the prescribed force with the derivative of the mechanical momentum, and [F4] supplies the coordinate work relation. If P=m(τ)U, differentiating g(U,U)=−c2 using metric compatibility gives g(U,DτU)=0; hence g(U,DτP)=m˙ g(U,U)+mg(U,DτU)=−c2m˙. This last identity imposes no dynamics for m.

Depends on

Dependency tree · 2 levels

Sources