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Ratio of isothermal and isentropic compressibilities

Physical scope

Finite whole-system compressibility and heat-capacity ratio on a positive-temperature C2 simple-compressible chart at fixed composition with valid isothermal and isentropic response inverses, positive isothermal compressibility, and positive constant-volume heat capacity.

Statement

On an open C2 Helmholtz chart at fixed composition n, assume T>0, CV>0, κT>0, and valid local response inverses for both the isothermal and isentropic compressibilities. Then Cp>0, κS>0, and

κTκS=CpCV.

The heat capacities are whole-system values; κS is defined in Isentropic compressibility on a valid local chart. The hypotheses exclude zero-capacity and singular-chart limits.

Facts & Assumptions

Given: The valid fixed-composition charts and positivity assumptions in the Statement.

[A1]

CV>0 and κT>0 are explicit response hypotheses on this chart; they are not inferred from notation alone.

[F1]

Thermodynamic response functions on valid local charts: CV=(∂U/∂T)V,n, Cp=(∂H/∂T)p,n, κT=−V−1Vp∣T,n, and αp=V−1VT∣p,n on the valid response chart; these definitions assert no identities between response functions.

[F2]

Isentropic compressibility on a valid local chart: κS=−V−1Vp∣s,n on a valid isentropic inverse chart.

[F3]

Differentials of the thermodynamic potentials: dU=T ds−p dV and dH=T ds+V dp on the named valid charts.

[F4]

Maxwell relations on valid thermodynamic potential charts: sV∣T,n=pT∣V,n.

[F5]

Heat-capacity relation on a stable response chart: Cp−CV=TVαp2/κT on the stated stable response chart.

[F6]

The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a): Differentiating a composition gives the usual total-derivative chain rule.

Proof

1.1givenA1F1F3F6algebra

By [F1], CV=UT∣V,n. On the fixed-volume path in the Helmholtz chart, [F3] gives dU=T ds; composing with the chart map and applying [F6] yields CV=TsT∣V,n. Likewise, by [F1], Cp=HT∣p,n, and on the fixed-pressure path in the Gibbs chart [F3] gives dH=T ds; the chain rule yields Cp=TsT∣p,n. Thus at fixed n, ds=(CV/T) dT+pT∣V,n dV. Along an isentrope ds=0, the valid chart gives TV∣s,n=−TpT∣V,n/CV.

2.1F4F6step 1.1algebra

Differentiate p(T,V,n) along the same isentrope using [F6]: pV∣s,n=pV∣T,n+pT∣V,nTV∣s,n=pV∣T,n−T(pT∣V,n)2/CV.

3.1A1F1F5F6step 2.1algebra

On the valid isothermal response inverse, p(T,V(T,p,n),n)=p. Differentiating this identity in p at fixed T,n gives 1=pV∣T,nVp∣T,n; by [F1] and κT>0, pV∣T,n=−1/(VκT). Differentiating it in T at fixed p,n gives 0=pT∣V,n+pV∣T,nVT∣p,n, so [F1] yields pT∣V,n=αp/κT. Thus [F5] is equivalently Cp−CV=−T(pT∣V,n)2/pV∣T,n. Substitution into step 2.1 yields pV∣s,n=pV∣T,n(Cp/CV). Since pV∣T,n<0 and CV>0, [F5] also gives Cp=CV−T(pT∣V,n)2/pV∣T,n≥CV>0, hence pV∣s,n<0.

4.1F1F2F6step 3.1algebra∎

On the valid isentropic inverse V=V(s,p,n), the identity p(s,V(s,p,n),n)=p gives 1=pV∣s,nVp∣s,n by [F6]. Hence the definitions [F1]–[F2] give κT=−1/(VpV∣T,n) and κS=−1/(VpV∣s,n). By step 3.1, κT/κS=pV∣s,n/pV∣T,n=Cp/CV. All denominators are nonzero by the valid-chart and positivity hypotheses.

Depends on

Dependency tree · 2 levels

Sources