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TheoremStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
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Conditional periodic kinetic H theorem

Statement

Let I be an open time interval in seconds and let Ω=∏j=13(R/LjZ), with fixed periods Lj>0 in metres. Give Ω the completed, unnormalised pushforward of Lebesgue measure on C=∏j=13[0,Lj) under the quotient map, as in the kinetic-density definition. Let f:Ω×R3×I→(0,∞) be C1 in (x,t) and C2 in v, with v measured in metres per second and f in the units assigned by the kinetic-density definition. Fix a constant fref>0 with the same units as f. Put ℓ=log⁡(f/fref), A=f(x,v,t)f(x,w,t), and B=f(x,v′,t)f(x,w′,t). Use the elastic collision set Qel={(v,w,v′,w′)∈R12:v+w=v′+w′, ∣v∣2+∣w∣2=∣v′∣2+∣w′∣2} with its relative Borel sigma-algebra and the nonnegative countably additive measure ν invariant under particle exchange in either pair and incoming/outgoing interchange, together with the weak operator Qν from the elastic-collision definition. Assume for each t that f, f∣v∣2, and f∣ℓ∣ are integrable over Ω×R3. On each compact time interval assume a common integrable envelope in (x,v) for ∣(1+ℓ)∂tf∣; at each t assume (1+∣ℓ∣)∣v⋅∇xf∣ is integrable over Ω×R3. In addition, assume f(1+∣v∣)∣ℓ∣,(1+∣ℓ∣)∣∂tf∣,(1+∣ℓ∣)∣v∣ ∣∇xf∣∈L1(I0×Ω×R3,dt dx dv)for every compact time interval I0⊂I, where each velocity integral is over all of R3, without a velocity cutoff. Thus the entropy density, entropy flux, and differentiation terms are integrable on compact time-space regions. Define D(x,t):=14∫Qel(A−B)log⁡(A/B) dν. Assume that D is measurable and locally integrable on I×Ω, and that for each t its spatial section belongs to L1(Ω). At every (x,t) assume f(x,⋅,t)∈Dν and 1,ℓ(x,⋅,t)∈Sf(x,⋅,t), with the measurability and absolute-convergence conditions of the elastic-collision definition. With δφ=φ(v)+φ(w)−φ(v′)−φ(w′), assume ∫R3φ(v)Qν(f)(v) dv=14∫Qel(B−A)δφ dν for those two tests, and suppose ∂tf+v⋅∇xf=Qν(f). Define h(x,t):=∫R3flog⁡(f/fref) dv,JH(x,t):=∫R3vflog⁡(f/fref) dv, H(t):=∫Ωh(x,t) dx,Dtot(t):=∫ΩD(x,t) dx. Then the local entropy balance holds in distributions: for every η∈Cc∞(I×Ω), ∫I∫Ω(h ∂tη+JH⋅∇xη−Dη) dx dt=0. Moreover, D(x,t)≥0 for almost every (x,t). The periodic global entropy H is differentiable and dHdt=−Dtot(t)≤0. The inequality is conditional on the adopted weak collision identity; it is not a derivation from reversible many-particle mechanics or a kinetic-PDE existence theorem.

Facts & Assumptions

Given: The positive regular periodic solution, time and spatial integrability envelopes, and absolutely convergent weak collision tests 1 and ℓ.

[F1]

Elastic collision measure and weak collision operator: The weak identity has factor 1/4 and is assumed for every declared test; the elastic set is invariant under incoming/outgoing and particle exchanges.

[F2]

Conditional Boltzmann entropy inequality and equality form: Under the same positivity, regularity, periodicity, entropy and time-derivative envelopes, spatial-transport integrability, and weak tests 1 and ℓ, the global functional H(t) is differentiable and has derivative −Dtot(t)≤0. That published Statement supplies the global identity only; the local distributional balance in this item is proved directly.

[F4]

Differentiation under the integral sign: The stated common L1 envelope permits differentiating the entropy integral in time.

[A1]

All hypotheses displayed in the Statement hold, including the local spacetime integrability, adopted PDE, and collision identity.

Proof

1.1A1F3F4F5algebra

By [F4], [F3], and the integrable entropy envelope, differentiation under the product integral gives H′(t)=∫Ω∫R3(1+ℓ)∂tf dv dx. Use [A1] to substitute ∂tf=Qν(f)−v⋅∇xf.

2.1A1F3F5step 1.1algebra

The transport contribution is −∫Ω∫R3(1+ℓ)v⋅∇xf dv dx=−∫Ω∫R3v⋅∇x(fℓ) dv dx, because ∇x(fℓ)=(1+ℓ)∇xf by [F3]. For each velocity coordinate, the integral of the corresponding periodic spatial derivative is zero by [F5]; the displayed integrability and Fubini justify integrating first in x. Thus only the collision contribution remains.

2.2A1F1F2F5step 1.1algebra

The test φ=1 has δφ=0, so [F1] gives ∫Qν(f) dv=0 at each x,t. The ℓQν(f) term is therefore the whole collision contribution. For φ=ℓ, the constant fref cancels from the four logarithms and δℓ=log⁡A−log⁡B=log⁡(A/B). The weak identity gives ∫ℓQν(f) dv=(1/4)∫(B−A)log⁡(A/B) dν=−D(x,t). Integrating in x is justified by the Statement's absolute-integrability hypothesis and yields H′(t)=−Dtot(t).

3.1A1F1F3F5step 2.2algebra

For η∈Cc∞(I×Ω), the product and chain rules give ∂t(fℓ)+v⋅∇x(fℓ)=(1+ℓ)(∂tf+v⋅∇xf). The local integrability hypotheses and Fubini [F5] permit integration against η and rearrangement of the (t,x,v) integrals. At each (x,t), the identity for test 1 gives ∫Qν(f) dv=0, while the identity for ℓ gives ∫ℓQν(f) dv=−D(x,t) because δℓ=log⁡(A/B). Integrating the resulting equation by parts in t and on the periodic torus yields the displayed local distributional balance.

4.1A1F1F2step 2.2algebra∎

Since A,B>0 and log⁡ is increasing, (A−B)log⁡(A/B)≥0 pointwise, with equality exactly when A=B. Its integral is nonnegative, so D(x,t)≥0 and therefore Dtot(t)≥0.

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