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Uniqueness of smooth periodic solutions and continuous dependence in Hs−1 on the common local interval

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). Let s≥4 be an integer, ν≥0, and let B>0 with T:=(2CsB)−1, where Cs is the commutator constant of The transport term is orthogonal to itself and the tame commutator estimate ∥[Λm,u⋅∇]u∥L2≤Cm∥u∥Hm∥u∥Hs. Let u0,v0∈Hσs(T3;R3)∩C∞(T3;R3) be smooth divergence-free data with ∥u0∥Hs≤B and ∥v0∥Hs≤B, and let u,v∈C∞([0,T]×T3;R3) be the corresponding smooth solutions of the projected equation ∂tu+P((u⋅∇)u)=νΔu given by Local smooth solutions of the periodic incompressible Euler and constant-viscosity equations on T3 (each nonzero datum has lifespan at least T by its norm bound; for a zero datum use the explicit solution z≡0 on [0,T], even when T>1).

  1. Uniqueness. If u(0)=v(0), then u=v on [0,T].
  2. Stability in L2. With w:=u−v and Θ:=sup⁡0≤t≤T∥∣∇v(t)∣∥L∞≤6Ws−1B, where ∣∇v∣=(∑j∣∂jv∣2)1/2 (Sobolev embedding on the torus: Hσ⊆Cj for σ>j+3/2, with continuous representatives), ∥w(t)∥L2≤eΘt∥w(0)∥L2(0≤t≤T).
  3. Continuous dependence in Hs−1. There is a finite constant K=K(s,B,T,ν) such that sup⁡0≤t≤T∥u(t)−v(t)∥Hs−1  ≤  K ∥u0−v0∥L21/s. In particular the solution map u0↦u is continuous from the bounded set Ds,B:={u0∈Hσs(T3;R3)∩C∞(T3;R3):∥u0∥Hs≤B} with its induced L2-topology into C([0,T],Hs−1).

Facts & Assumptions

Given: The two smooth solutions u,v on [0,T], the difference w=u−v and the constant Θ.

[F1]

For smooth fields on T3: ∫T3∂jf dx=0 and ∫T3f∂jg dx=−∫T3(∂jf)g dx (periodic integration by parts); ⟨Δf,f⟩=−∥∇f∥L22 (Periodic vector Sobolev spaces on the three-torus, the weight family, and the Leray projection, The Lebesgue integral is linear on L1(μ), Integral over a measurable subset).

[F2]

Vanishing transport integral: for divergence-free u∈Hm, m>5/2, and w∈Hm, ∫((u⋅∇)w)⋅w dx=0; here s≥4>5/2 and all fields are smooth (The transport term is orthogonal to itself and the tame commutator estimate ∥[Λm,u⋅∇]u∥L2≤Cm∥u∥Hm∥u∥Hs, claim 1).

[F3]

Sup bound: for s−1>3/2, ∥∇v(t)∥L∞≤3Ws−1∥v(t)∥Hs and ∥v(t)∥Hs≤2B on [0,T], with the latter established by the smooth energy argument in step 1.1 below (Sobolev embedding on the torus: Hσ⊆Cj for σ>j+3/2, with continuous representatives, claims 3 and 4; The transport term is orthogonal to itself and the tame commutator estimate ∥[Λm,u⋅∇]u∥L2≤Cm∥u∥Hm∥u∥Hs, claims 2-3).

[F4]

Interpolation: for real fields with finite norms, ∥f∥Hs−1≤∥f∥L21/s∥f∥Hs(s−1)/s for every integer s≥1 (Holder's inequality for finite sums and conjugate real exponents applied to the families ak=∣f^(k)∣2/s and bk=wk2(s−1)∣f^(k)∣2(s−1)/s, followed by the supremum over finite sets).

[F5]

Gronwall: if continuous y≥0 satisfies y(t)≤A+∫0tλy with A,λ≥0 constants, then y(t)≤Aeλt (Gronwall's integral inequality with variable and constant coefficients).

[F6]

Two continuous fields equal almost everywhere are equal everywhere, and the L2 norm of a field is (∑k∣f^(k)∣2)1/2 (Sobolev embedding on the torus: Hσ⊆Cj for σ>j+3/2, with continuous representatives, claim 2; Periodic vector Sobolev spaces on the three-torus, the weight family, and the Leray projection).

Proof

technique · direct; insert the difference of the two equations into the $L^2$ energy identity, bound the difference term by the sup norm of the gradient, integrate the resulting linear inequality by Gronwall, and interpolate

Given: The smooth solutions u,v of the projected equation, the difference w=u−v and the facts [F1]-[F6].

1.1givenF1F2algebra

For either smooth solution z=u or z=v, put Y(t)=∥z(t)∥Hs. Pair its equation with Λ2sz, using periodic integration by parts and the commuting orthogonal Leray projection. The dissipative term is nonpositive since ν≥0, while claims 2-3 of The transport term is orthogonal to itself and the tame commutator estimate ∥[Λm,u⋅∇]u∥L2≤Cm∥u∥Hm∥u∥Hs give 12(Y2)′≤CsY3. With Yε=(Y2+ε2)1/2 this implies Yε′≤CsYε2, hence Yε(t)≤Yε(0)/(1−CsYε(0)t) while the denominator is positive, by differentiating 1/Yε. Letting ε↓0 gives Y(t)≤Y(0)/(1−CsY(0)t)≤2B for t≤T=(2CsB)−1; if Y(0)=0 the same limit gives Y=0. This establishes the bound required in [F3] for both solutions, without substituting 2B for the weaker exponential bound in the existence supplier.

1.2givenF6

Subtracting the equations for u and v and writing u=v+w, we get (u⋅∇)u−(v⋅∇)v=(v⋅∇)w+(w⋅∇)v+(w⋅∇)w=(u⋅∇)w+(w⋅∇)v, so w solves w′=νΔw−P((u⋅∇)w+(w⋅∇)v); w is smooth, real and divergence-free.

2.1step 1.2F1F2F5

Pairing the equation for w with w and using that P is self-adjoint and fixes divergence-free fields, 12ddt∥w∥L22=⟨w′,w⟩=−ν∥∇w∥L22−⟨(u⋅∇)w,w⟩−⟨(w⋅∇)v,w⟩. By [F2] the middle term vanishes, and the pointwise bound ∣∑jwj(∂jv⋅w)∣≤∣∇v∣ ∣w∣2 gives ∣⟨(w⋅∇)v,w⟩∣≤∥∣∇v∣∥L∞∥w∥L22; hence 12ddt∥w∥L22≤Θ∥w∥L22. Integrating this differential inequality gives ∥w(t)∥L22≤∥w(0)∥L22+2Θ∫0t∥w(σ)∥L22dσ, and Gronwall [F5] yields the stability estimate of claim 2.

3.1step 2.1F3

Θ≤6Ws−1B by [F3]: pointwise ∣∇v∣≤∑j=13∣∂jv∣ so ∥∣∇v(t)∣∥L∞≤∑j=13∥∂jv(t)∥L∞≤3Ws−1∥v(t)∥Hs≤3Ws−1⋅2B.

3.2step 2.1F6

Uniqueness: if u(0)=v(0) then ∥w(0)∥L2=0, so ∥w(t)∥L2=0 for all t≤T by step 2.1; hence w=0 almost everywhere, and since w is continuous, w=0 everywhere by [F6]; this is claim 1.

4.1step 1.1step 2.1step 3.1F3F4

Continuous dependence: by [F4] applied to w(t) and by the bounds for both solutions in step 1.1, ∥w(t)∥Hs−1≤∥w(t)∥L21/s∥w(t)∥Hs(s−1)/s≤(eΘT∥w(0)∥L2)1/s(4B)(s−1)/s. Taking the supremum over t∈[0,T] and using Θ≤6Ws−1B gives claim 3 with the uniform constant K:=e6Ws−1BT/s(4B)(s−1)/s, which is finite and independent of the data and ν.

5.1givenstep 3.2step 2.1step 4.1∎

Claims 1-3 are established by steps 3.2, 2.1 and 4.1. Existence and uniqueness give a well-defined solution map on Ds,B, and step 4.1 makes its output distance tend to zero whenever its input L2 distance tends to zero, proving the stated continuity.

Remarks

  • Uniqueness is asserted among the smooth solutions constructed on the common interval; no weak-solution class is involved. The stability exponent is controlled by the Hs bound of the comparison solution, so the modulus of continuity is explicit in the size of the data.
  • The exponent 1/s in the Hs−1 stability is the Hölder exponent produced by interpolation; no Lipschitz stability in the high norm is claimed.

Depends on

Dependency tree · 2 levels

Sources