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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-11-04 (gpt-6.1-sol)
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Global cotangent-complex obstruction and lifting torsor

Statement

Assume the Axiom of Choice. Let A′↠A be a small extension of local Artin k-algebras with residue field k and square-zero kernel I, and let X be a flat, locally finitely presented A-scheme with a specified reduction X0. The marked relative lifting problem fixes the whole A-scheme X and the identification of its reduction. The source result asserts a canonical obstruction in Ext⁡OX2(LX/A,OX⊗AI), vanishing exactly when a lift exists; when nonempty, marked isomorphism classes form an Ext⁡1-torsor and lift automorphisms inducing the identity on X are Ext⁡0. If X is smooth over A, then TX/A:=HomOX(ΩX/A1,OX) and the obstruction group is H2(X,TX/A⊗AI).

Extension diagram

The top row is the prescribed base thickening and the bottom row is the marked sheaf extension to be constructed. The map c sends i to 1⊗i. All sheaves in the diagram are viewed on the underlying space of X; base rings denote their inverse-image sheaves.

0IA0A00OX¬AIOX0OX0c

Facts & Assumptions

Given: the small extension A′↠A, its square-zero kernel I, the flat locally finitely presented A-scheme X, its specified reduction X0, and AC.

[F1]

Marked algebra and sheaf extensions from polynomial presentations proves extension classification in all sheaves of modules, including the restriction fiber and automorphisms; it does not assume global polynomial-generator lifts or projectivity of polynomial sheaves.

[F2]

Scheme effectivity and flatness for marked Artin lifts proves scheme effectivity of quasi-coherent square-zero kernels and equivalence, for this exact kernel, with flat locally finitely presented scheme lifts over Artin bases.

[F3]

The cotangent complex of a morphism of schemes supplies the global sheaf-ring complex, the canonical transitivity triangle and affine comparisons; Ext groups of the cotangent complex defines global derived Ext.

[F4]

Truncation, differentials and the cotangent complex of a smooth morphism gives H0(L)=Ω, the degree-zero and degree-one truncation comparisons, and the smooth locally free differential identification.

[F5]

Affine square-zero lifting obstruction, torsor, and automorphisms proves the corresponding marked affine obstruction and fiber. Flat deformations form a Zariski sheaf of groupoids supplies compatible-lift descent; no arbitrary local lifts are assumed compatible.

[A1]

The Axiom of Choice is inherited from [F1]–[F5].

Proof

Given: [F1]–[F5], [A1] and the Statement's data. Put S=Spec⁡A, S′=Spec⁡A′, let f:X→S be the given map, and put M=OX⊗AI.

1.1F3F4A1givenconstruct

Write C=Lf∗LS/S′, K=LX/S′, and L=LX/S. The conormal presentation of the surjection A′→A identifies τ≥−1LS/S′ with I~[1]. Since f is flat, C lies in degrees at most −1 and H−1(C)=M. Hence Ext⁡OX0(C,M)=0 and Ext⁡OX1(C,M)=Hom⁡OX(M,M). This is a global calculation: the part in degrees at most −2 has derived Hom into a degree-zero module zero in degrees below two, so truncation gives these identities without replacing global Ext by local sections of a sheaf Ext. Let γ be the identity of M, equivalently the map induced by c:i↦1⊗i.

2.1F1F3step 1.1algebra

By [F1], Ext⁡OX1(K,M) classifies square-zero f−1OS′-algebra sheaves 0→M→E→OX→0. Restriction to the base followed by coefficient change is the map to Ext⁡OX1(C,M). In the conormal presentation of A′→A it sends an extension to its structural multiplication map I⊗AOX→M: evaluating the relation i∈I gives exactly its structural image in E. The sheaf-generator proof and naturality in [F1] show this equality globally, so it includes the required gluing of algebra data. Thus the fiber over γ is exactly the marked sheaf-ring lifting problem with the prescribed kernel map. No overlap choices or triple-overlap obstructions have been suppressed by an appeal to affine descent.

3.1F1F3step 1.1step 2.1constructalgebra

The canonical triangle C→K→L→C[1] gives the exact sequence Ext⁡1(K,M)→Ext⁡1(C,M)→∂Ext⁡2(L,M), all groups taken globally over OX. Define o(X,A′)=∂γ. It vanishes exactly when the fiber in step 2.1 is nonempty. The preceding exact sequence, beginning with Ext⁡0(C,M)=0, injects Ext⁡1(L,M) into Ext⁡1(K,M) with image the kernel of restriction. Each nonempty fiber is therefore a torsor for Ext⁡1(L,M). The boundary is canonical because both the global sheaf-ring cotangent triangle and the class γ are canonical; [F1]'s presentation comparisons prove that constructing the fiber with different sheaves of generators gives the same class and action.

4.1F2step 2.1step 3.1algebra

The module M is quasi-coherent, and in every extension in this fiber the structural multiplication map onto its kernel is the identity of M. Apply [F2]: (∣X∣,E) is a scheme X′ flat and locally finitely presented over A′, with IX′=M at the sheaf level and X′×A′A=X with exactly its given marking. Conversely every flat lift has kernel canonically I⊗AOX and structural map c, so gives precisely an object of this fiber. Isomorphisms in the two problems agree by [F2]. This proves the existence criterion and torsor for scheme lifts, rather than merely for abstract ringed-space extensions. Composing the unchanged X-marking with the specified marking of X0 preserves the latter automatically.

5.1F1F2F3F4F5step 2.1step 4.1algebra

The automorphism calculation in [F1] gives global derivations OX→M over A′, which are the same as those over A because A′↠A. They are Hom⁡OX(ΩX/A1,M)=Ext⁡OX0(L,M) by [F4], with additive composition as in [F1]. By step 4.1 these are exactly the scheme-lift automorphisms inducing the identity on X; their action on the kernel is forced to be the identity because that kernel is generated by I. On affine restrictions the boundary, the kernel map and the automorphism calculation coincide with [F5]'s affine theorem by the affine comparison and the evaluation calculation of step 2.1. Compatible such restrictions glue as in [F5]; this checks agreement of the two interfaces without using compatible-lift descent as the construction of o.

6.1F3F4step 3.1step 4.1step 5.1algebra∎

If X/A is smooth, [F4] gives L≃ΩX/A1[0] with ΩX/A1 finite locally free. Internal Hom from this module is exact, so an injective resolution computes global derived Hom as RΓ(X,Hom(ΩX/A1,M)). Locally choosing a finite basis identifies this internal Hom canonically with TX/A⊗AI; these basis-independent evaluation maps agree on overlaps. Thus Ext⁡2(L,M)=H2(X,TX/A⊗AI) and the already constructed obstruction lies in the group in the Statement. This makes no claim that the group vanishes on a general X. The zero-kernel case has M=0, the zero obstruction and the unique trivial marked lift. All required conclusions follow.

Depends on

Dependency tree · 2 levels

Sources