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The Poincare inequality for zero-boundary Sobolev closures on domains bounded in one direction
Statement
Assume Countable Choice (The Axiom of Countable Choice ()). Let be open and bounded in one direction: there are a unit vector and with for every . Let . Then for every .
Facts & Assumptions
Given: Countable Choice; an open set bounded in the direction between ; an exponent ; a field ; and a class .
is the closure in of the compactly supported smooth functions , and every such smooth function lies in with its classical derivatives as weak derivatives (Zero-boundary Sobolev space as a norm closure).
Riemann vector-valued fundamental theorem: if is differentiable with integrable derivative, then (If is differentiable with integrable then ; and a bounded derivative makes Lipschitz).
Holder's inequality for integrals (Holder's inequality for integrals, including the endpoint cases).
Tonelli's theorem on sigma-finite products, allowing iterated integrals of nonnegative measurable functions in either order (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product).
Linear set-measure scaling: an invertible linear map of scales Lebesgue measure by (A linear map of sends Lebesgue measurable sets to Lebesgue measurable sets, with when is invertible and Lebesgue null when it is not). This set formula is distinct from the integrand substitution in [F9].
consists of classes with weak derivatives in and the norm is the norm of and its coordinate weak derivatives (Integer-order Sobolev spaces and their norms); classes are almost-everywhere classes (The space as the quotient by null functions).
Countable Choice, assumed for the measure and closure interfaces above (The Axiom of Countable Choice ()).
A continuous real function on a compact nondegenerate interval is bounded and Riemann integrable; under Countable Choice its Riemann and Lebesgue integrals agree (Every continuous function on a closed nondegenerate rectangle in is Riemann integrable, A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral).
Under Countable Choice, a diffeomorphism between open subsets of satisfies for every nonnegative Lebesgue measurable (A C^1 diffeomorphism satisfies the change-of-variables formula for nonnegative Lebesgue measurable functions).
The Lebesgue integral of a complex integrable function is the integral of its real part plus times the integral of its imaginary part, and for real or complex integrable (Integrable real and complex functions, and their integrals, The modulus of an integral is bounded by the integral of the modulus).
Proof
The smooth case: pointwise bound. Let and extend it by zero to . Write with . For each fixed , the profile is smooth and supported in , since . If , then and . On , each real component of is continuous, so [F8] supplies its Riemann integrability and converts its Riemann integral to its Lebesgue integral. Thus [F2] applied componentwise and the complex integral convention in [F10] give . The continuous derivative and its modulus are Lebesgue integrable on this compact interval by [F8]; [F10] and therefore give . For the resulting integral bound is already the desired estimate; for , Holder [F3] applied to the real nonnegative function and the constant , followed by and enlargement of the integration interval, yields .
The smooth case: integration. If , then , so integrating step 1.1 gives by [F9] for the global linear diffeomorphism of (where or and the absolute Jacobian is ), and the support of in . Now suppose . Choose orthonormal coordinates with last vector and write ; the corresponding orthogonal map is a global diffeomorphism with . By [F9], nonnegative integrands have the same integral after composing with ; this applies both to and to , which are Borel measurable since the zero extension is smooth and is open. For each , the slice is a measurable subset of , so . Integrating step 1.1 over and applying Tonelli [F4] gives . The last integral equals , since and its gradient vanish outside and lies in the slab. Therefore .
The general class. By [F1] there are with in ; by step 2.1, for every . Both sides are continuous in the norm: and by [F6]. Passing to the limit gives , so the asserted inequality holds with .
Source notes
Kinnunen's Theorem 3.10 proves the estimate on bounded open sets by taking the primitive in one coordinate direction and applying Holder; the proof above runs the same argument along the unit vector of the hypothesis, uses the orthonormal coordinate decomposition for the integration, and then extends from to by the definition of the latter as a closure. The constant obtained is , independent of ; the statement permits a -dependent constant.
Depends on
Zero-boundary Sobolev space as a norm closure
If is differentiable with integrable then ; and a bounded derivative makes Lipschitz
Holder's inequality for integrals, including the endpoint cases
Tonelli's theorem for nonnegative measurable functions on a sigma-finite product
A linear map of sends Lebesgue measurable sets to Lebesgue measurable sets, with when is invertible and Lebesgue null when it is not
Integer-order Sobolev spaces and their norms
The space as the quotient by null functions
The Axiom of Choice
The Axiom of Countable Choice ()
Every continuous function on a closed nondegenerate rectangle in is Riemann integrable
A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral
A C^1 diffeomorphism satisfies the change-of-variables formula for nonnegative Lebesgue measurable functions
Integrable real and complex functions, and their integrals
The modulus of an integral is bounded by the integral of the modulus
Dependency tree · 2 levels
Sources
- Juha Kinnunen, Sobolev Spaces (Aalto University, 2026, complete graduate lecture notes)
- John K. Hunter, Notes on Partial Differential Equations (UC Davis, revised 18 June 2014, complete 242-page two-quarter notes)
- Gerald Teschl, Partial Differential Equations: From Classical to Modern (archived 2025 author manuscript)