Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Unique lifts, endpoint fibres and characteristic subgroups

Statement

Let p:E→G be a functor of small groupoids, with E,G connected and nonempty, bijective from the arrows with source e to those with source p(e) for every e. Such a functor is called a covering. Put x=p(e) and H=p(Ee)≤Gx (the characteristic subgroup at e). Products of arrows are read left to right. Lifts preserve products and inverses, Ee→Gx is injective, and two arrows a,b:x→y lifted from e have equal endpoints exactly when ab−1∈H.

Facts & Assumptions

[F1]

Use the small-groupoid, functor and vertex-group conventions of Set-sized groupoids, functors and composition conversion. A subgroup means a subset containing the identity and closed under multiplication and inverses. The assumed source-wise bijections are the definition of covering.

Proof

Given: The data and hypotheses in the Statement.

Goal: Establish all assertions of the Statement.

1.1F1

For composable arrows a,b, lift a from u, then b from its endpoint. Their composite projects to ab and has source u, hence is its unique lift. Identity arrows lift to identities, and the inverse of a lift projects to the inverse arrow and is its unique lift from its source. This uses exactly preservation of composition and the source-wise bijection.

2.1F1step 1.1∎

Two loops at e with equal images are equal by injectivity on arrows with source e. Their image H contains the identity and is closed under products and inverses, so is a subgroup. If the lifts of a,b have equal endpoints, their first composite with the inverse of the second is a loop over ab−1, giving membership in H. Conversely lift ab−1∈H as a loop at e, and then compose with the lift of b from e. This projects to a and ends where that lift of b ends; uniqueness gives the assertion.

Depends on

Used by · 5

Dependency tree · 2 levels

Each result is drawn at its shortest distance from this item. Arrows run from prerequisites to the items that use them; this item has a heavier outline. External source nodes link directly to the cited text. The view shows up to two dependency steps; open a prerequisite to continue.

Sources