Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Explicit connected cover associated with a vertex subgroup

Statement

Let G be a connected small groupoid, x an object, and H≤Gx a subgroup. Form objects Ha={ha:h∈H} for all arrows a:x→y, recording y. There is a connected covering CH→G whose arrows are pairs (Ha,g) with g:y→z, from Ha to Hag, projecting to g. Its chosen object is H1x=H and its characteristic subgroup there is H.

Facts & Assumptions

[F1]

Use Set-sized groupoids, functors and composition conversion for small groupoids and left-to-right products, and Unique lifts, endpoint fibres and characteristic subgroups for coverings and characteristic subgroups; a subgroup contains the identity and is closed under multiplication and inverses.

Proof

Given: The data and hypotheses in the Statement.

Goal: Establish all assertions of the Statement.

1.1F1

Two sets Ha,Hb with the same recorded target coincide precisely when a=hb for some h∈H, equivalently ab−1∈H. Indeed a nonempty intersection yields h1a=h2b and hence a=h1−1h2b; the converse follows by closure of H. Consequently replacing a by ha leaves Hag unchanged. These are sets because G is small.

2.1F1step 1.1∎

Define (Ha,g)(Hag,k)=(Ha,gk). Associativity follows from that of G; the identity at Ha is (Ha,1y) and the inverse of (Ha,g) is (Hag,g−1). Thus this is a groupoid and the projection is a functor, bijective on each source star since its arrows with prescribed source are exactly the pairs with all possible labels g. Between Ha and Hb the label a−1b gives an arrow, so it is connected. The loops at H have precisely labels g∈Gx with Hg=H, exactly H, which proves the characteristic-subgroup claim.

Depends on

Used by · 4

Dependency tree · 2 levels

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Sources