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Adjacent relative chambers force a finite crossing component
Statement
In the finite-rank canonical Coxeter representation, fix and let label adjacent relative chambers . Let be the index of their common wall, and put and . Then In particular is finite, where is the vertex set of the connected component containing in the Coxeter diagram induced on .
Facts & Assumptions
The common wall is the facet at and the two chambers are on opposite sides of its supporting hyperplane, by Common relative facets have one enlarged standard subset.
Roots have one sign, dual evaluation obeys , and , by Root signs, inversions and descent translation.
The roots of a standard parabolic are exactly the ambient roots supported on its vertex subset, by Intersections of standard parabolics, the parabolic root subsystem, and global minimality of coset representatives, part (2).
Finiteness of implies finiteness of by Finite root difference forces finite connected parabolic.
For , is the subspace annihilating the simple roots indexed by , and consists of its points strictly positive on all remaining simple roots. A relative chamber has , and its wall at has supporting relative hyperplane , where . These coordinate-face and wall descriptions are supplied by Convexity, stratification and faces of the relative cone.
The notation denotes the vertices of the connected component containing in the Coxeter diagram induced on , by Connected component notation [I,a].
Proof
Given: The finite-rank canonical Coxeter representation, root basis and dual action, with the notation and hypotheses in the Statement. Goal: prove the stated assertions.
Proof technique: direct.
Let . By [F2, F3], its simple-root coefficients are nonnegative, supported on , and its coefficient at is strictly positive. Thus for every . By [F5], the positive coordinate orthant spans , so implies . Since , the subspaces have the same finite dimension and . Dual evaluation now gives for every .
For with , [F5] gives . The common wall's supporting hyperplane is exactly by [F5]. Consequently [F1] puts all of in the half-space where . Since , step 1.1 shows that evaluation on is positive on and negative on .
Choose , which is nonempty since one may prescribe value zero on the basis roots indexed by and value one on the others, by [F5]. Then by step 2.1 and [F2]. The root cannot be positive: a positive root has nonnegative simple-root coefficients, whereas has nonnegative values on every simple root by [F5], so its evaluation would be nonnegative. Thus is negative by [F2], and .
The positive part of the root difference has at most members by [F2] and step 3.1. By [F2, F3], negation is a bijection from its positive part to its negative part, and the two parts are disjoint. Hence . Apply [F4] with the component of [F6] to obtain finiteness of . This uses a finite inversion set, regardless of the size or type of or .
Depends on
- Common relative facets have one enlarged standard subset
- Root signs, inversions and descent translation
- Intersections of standard parabolics, the parabolic root subsystem, and global minimality of coset representatives
- Finite root difference forces finite connected parabolic
- Convexity, stratification and faces of the relative cone
- Connected component notation [I,a]
Dependency tree · 2 levels
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