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Length additivity and the base-chamber half-space

PDF p. 11: Lemma 3.20(2)

Statement

Let (W,S) be a finite-rank Coxeter system with simple generators si and simple roots αi indexed by Γ0. Use its standard geometric representation, root signs, word length ℓ, dual space Θ, and contragredient action. For L⊆Γ0, write WL=⟨si:i∈L⟩. Fix J⊆Γ0 and a label (x,I)∈Cham(J), so WJx=xWI and x has minimum length in xWI. The label represents the relative chamber xCI, where CI consists of dual vectors vanishing on αi for i∈I and positive on the other simple roots.

Choose a∉I, let D=[I,a] be the component containing a of the diagram induced on I∪{a}, and suppose WD is finite. Put va,I=wD∖{a}wD, using the longest elements of the indicated finite parabolics. Suppose the pair ωa,I(x,I) is a label adjacent to (x,I). Then ℓ(xva,I)=ℓ(x)+ℓ(va,I) if and only if the base chamber CJ and xCI lie in the same open half-space of Hxαa={f∈Θ:f(xαa)=0}.

Facts & Assumptions

[F1]

Roots have exactly one sign, and for N(w)={β∈Φ+:wβ∈Φ−} one has ∣N(w)∣=ℓ(w)=ℓ(w−1). Root signs, inversions and descent translation

[F2]

A minimal representative x of xWI satisfies ℓ(xsi)>ℓ(x) for every i∈I; the root-length criterion then gives xαi∈Φ+. Support, intrinsic parabolic presentations, minimal coset representatives and length additivity, with the type-A identification The root-length criterion and faithfulness of the canonical reflection representation

[F3]

For Q=D and Q=E=D∖{a}, the standard subsystem has root set ΦQ=Φ∩span⁡{αi:i∈Q} with the inherited signs, by part 2 of Intersections of standard parabolics, the parabolic root subsystem, and global minimality of coset representatives. The longest elements wD,wE are involutions and send their respective positive subsystem roots to negative roots. Finite parabolic longest elements and disconnected factors

[F5]

The label (x,I) represents xCI in the relative space ΘJ={f:f(αj)=0 for j∈J}, and the base label (1,J) represents CJ. The dual action obeys (xf)(β)=f(x−1β). Labelling theorem for relative chambers Coxeter-system, roots, length and weak-order conventions

Proof

Given: The finite-rank Coxeter data, label, vertex a, finite component D, and adjacency in the Statement. Put E=D∖{a} and v=wEwD.

Proof technique: direct.

Goal: Prove the equivalence between length additivity and the stated same-half-space condition.

1.1F1F3F4given

Inversions of the crossing element. Every generator indexed by E changes only its own simple-root coordinate. Thus wE preserves the coefficient of αa. If β∈ΦD+ has positive αa coefficient, then wEβ is a root with positive αa coefficient and hence is positive by [F1]. If that coefficient is zero, [F3] identifies β with a root of ΦE+, and wEβ is negative. Since wD exchanges the two signs in ΦD and v−1=wDwE, it follows that N(v−1)∩ΦD=ΦD+∖ΦE+. By [F4] all inversions of v−1 lie in ΦD, so this is the entire inversion set. In particular αa∈N(v−1).

2.1F1F2step 1.1

Length criterion. For arbitrary u,t∈W, partitioning positive roots by the signs of t−1β and uβ gives ℓ(ut)=ℓ(u)+ℓ(t)−2∣N(u)∩N(t−1)∣. Indeed, the roots in the intersection are precisely the cancellations between inversions of t and those of u, after the sign-preserving bijection induced by t on the other sign classes; all sets involved are finite by [F1]. Consequently ℓ(xv)=ℓ(x)+ℓ(v) exactly when x sends every root in N(v−1) to a positive root. By [F2], xαi is positive for i∈E. If xαa is positive, every positive root supported on D is a nonzero nonnegative combination of simple roots whose images are positive, so its image is positive. Conversely, αa itself belongs to N(v−1) by 1.1. Therefore length additivity is equivalent to xαa∈Φ+.

3.1F1F5step 2.1given∎

Translate to half-spaces. For f∈CI, the dual-action formula gives (xf)(xαa)=f(αa)>0. Hence the linear functional g↦g(xαa) is nonzero on ΘJ, because xCI⊆ΘJ by [F5]. Write xαa in the simple-root basis. By [F1] its nonzero coefficients all have the same sign, and nonvanishing on ΘJ means at least one coefficient outside J is nonzero. Every g∈CJ vanishes on the J coordinates and is strictly positive on the others, so g(xαa)>0 exactly when xαa is positive, and is negative otherwise. Thus CJ and xCI are in the same open half-space of Hxαa exactly when xαa is positive. Combining this with step 2.1 proves the assertion.

Source notes

The article citation records attribution of the retained claim. The proof above uses the declared suppliers and does not invoke the article's claim as a premise.

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