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Basic Tits-cone properties

PDF p. 5: §2.2; PDF p. 7: §3.1; PDF p. 8: opening of Lemma 3.5 argument

Statement

Let (W,S) be a Coxeter system with S finite, with the canonical real reflection representation, its dual space Θ, the contragredient W-action, the closed fundamental chamber C‾, the Tits cone Cone=⋃w∈WwC‾, and the set H of distinct root hyperplanes as in Reflecting hyperplanes, fundamental chamber and Tits cone. Use the finite-dimensional topology specified there.

The Tits cone is a W-invariant convex cone. The chamber C‾ is a fundamental domain in the sense that every W-orbit in Cone meets it in exactly one point. The arrangement (Cone∘,H) is locally finite: every point of Cone∘ has a neighbourhood in Θ meeting only finitely many members of H. Finally, W is finite if and only if Cone=Θ.

Facts & Assumptions

[F1]

The contragredient maps form a W-action and Cone=⋃w∈WwC‾. The hyperplanes in H are the distinct root hyperplanes. Reflecting hyperplanes, fundamental chamber and Tits cone

[F2]

For this finite-rank representation, the union U=⋃w∈WwC‾ is a convex cone, every orbit in U meets C‾ exactly once, the distinct root hyperplanes are locally finite on U∘, and U=Θ exactly when W is finite. Tits cone geometry with its exact interior boundary

Proof

Given: The finite-rank Coxeter system and the geometric notation in the Statement.

Proof technique: direct.

Goal: Prove the four assertions about the Tits cone, its fundamental domain, local finiteness and finiteness of W.

1.1F1F2given

By [F1], for any g∈W the action law gives gCone=⋃w∈WgwC‾=⋃v∈WvC‾=Cone, since multiplication by g permutes W. By [F2], the same union is a convex cone and every orbit in it meets C‾ exactly once. This proves invariance, convexity and the stated fundamental-domain property.

2.1F1F2step 1.1∎

The definitions in [F1] identify Cone with the set U in [F2] and H with its distinct root hyperplanes. Thus the local-finiteness assertion in [F2] gives the stated neighbourhood condition on Cone∘, and its final assertion gives W finite if and only if Cone=Θ. Together with 1.1 this proves the proposition.

Depends on

Used by · 8

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Sources