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Normaliser-action wording in the D4 exposition
PDF p. 29: §7.2.1, paragraph beginning “By Theorem 4.7”
Statement
In the example, vertex is central, , and . The normaliser is and . A relative chamber has a unique label satisfying and with of minimum length in ; it is the face translate .
The induced action of on these chambers is free: a quotient element fixing a chamber is the identity. Two chambers are in the same orbit, meaning that one is the image of the other under a quotient element, exactly when their second labels agree. There are four orbits, indexed by , each containing eight chambers.
The article's paragraph instead says that the action of each is free. The quotient formulation above makes the intended freeness precise: the nonidentity element acts trivially on every relative chamber.
Statement references
Facts & Assumptions
The quotient action is induced by the normaliser action on the relative dual space; its kernel before quotienting is , and a lift sends to . Faithful normaliser-quotient action on the relative cone Normalisers and their quotients
Labels satisfy and correspond bijectively to chambers . Algebraic chamber-label set Labelling theorem for relative chambers
Each orbit in the Tits cone meets the closed fundamental chamber in exactly one point, and the stabiliser of every point of is . Tits cone geometry with its exact interior boundary
In the completed chamber list, each of the singleton second labels occurs exactly eight times and there are no other labels. D4 diagram and generator conventions D4 chamber labels and complete adjacency graph
Proof
Given: The data and in the Statement. Write for the fundamental face with zero simple-root coordinates exactly at .
Proof technique: direct.
Goal: Establish freeness, the orbit criterion and the stated correction to the normaliser wording.
Suppose a normaliser element sends the chamber to . Choose . Then , where . Both and lie in the closed fundamental chamber and in the same orbit. By [F3], ; their zero coordinates therefore give , and [F3] also gives . In particular, if and , then by [F2]. Hence a quotient element fixing a chamber is the identity, proving freeness.
Conversely, let and be labels with the same second component. By [F2], both and equal . Thus normalises , and [F1] sends to . Together with step 1.1, this proves the orbit criterion. Counting the labels in [F4] gives four orbits of eight chambers.
The reflection formula in the data gives , so . It belongs to and hence acts trivially on the relative space and its chambers by [F1]. Therefore the normaliser action itself is not free, whereas its quotient action is free by step 1.1. This completes the clarification.
Source notes
The article reference attributes the wording in its discussion. The proof uses the listed completed suppliers and does not take that wording as a premise.
Depends on
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Sources
- Normalisers of parabolic subgroups of Artin–Tits groups and Tits cone intersections · PDF p. 29, §7.2.1, paragraph beginning ‘By Theorem 4.7’