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Cut-edge mixing bound — Lemma 3.4

PDF p. 19: Lemma 3.4; PDF p. 20: Lemma 3.4

Statement

Let G=(V,E) be an (n,d∗,α,c−,c+)-expander as in Two-sided spectral expander — Definition 1.9, and let X⊆V. Write Xc=V∖X and let e(X,Xc) be the ordered edge count of Oriented edge count between sets. Then

c−d∗n∣X∣∣Xc∣≤e(X,Xc)−d∗n∣X∣∣Xc∣≤c+d∗n∣X∣∣Xc∣.

Facts & Assumptions

[F1]

The expander definition has n=∣V∣>0, ΔL=L−d∗I+(d∗/n)J, and c−d∗I⪯ΔL⪯c+d∗I. Here L is the row-sum Laplacian, I is the identity, and J is the all-ones matrix (Two-sided spectral expander — Definition 1.9).

[F2]

For Hermitian matrices, B⪯C means that ⟨f,(C−B)f⟩≥0 for every complex vector f, with ⟨f,g⟩=∑x∈Vf(x)‾g(x) (Loewner order, Hermitian inner product, and operator norm).

[F3]

If 1X and 1Xc are the indicators of X and Xc and f=∣Xc∣1X−∣X∣1Xc, then ⟨f,f⟩=n∣X∣∣Xc∣ and ⟨f,ΔLf⟩=n2(e(X,Xc)−(d∗/n)∣X∣∣Xc∣) (Cut test-vector identities for Laplacian mixing).

Proof

Given: An expander G and a subset X⊆V as in the statement.

Goal: Establish both displayed bounds on the centered cut count.

1.1F1F2F3

Take the cut vector f of [F3]. Applying the two order inequalities in [F1] to this vector using [F2] yields c−d∗⟨f,f⟩≤⟨f,ΔLf⟩≤c+d∗⟨f,f⟩. This application is valid also when f=0.

2.1F1F3step 1.1algebra∎

Substitute the two identities in [F3] into step 1.1 and divide throughout by n2>0, using n>0 from [F1]. The result is precisely the asserted pair of inequalities. This includes X=∅ and X=V.

Source notes

The statement and the cut-vector method are attributed to Lemma 3.4 of Expander graphs are globally synchronizing. The argument above derives the claim from the stated local suppliers.

Depends on

Used by · 4

Dependency tree · 2 levels

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Sources