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Convex adjacency norm: sharp coordinate constant and median counterexample

PDF p. 35: Proof of Corollary 6.6

Statement

Let n≥2, 0<p<1, and let X consist of the d=(n2) independent Bernoulli-p edge coordinates of the loop-free graph G(n,p). Let T(x) have zero diagonal and symmetric off-diagonal coordinates x, let J be the all-ones matrix, and use the Euclidean coordinate metric and Euclidean operator norm. The function f(x)=∥T(x)−pJ∥ is convex; its sharp Lipschitz constant on [0,1]d is 2(n−1)/n, which exceeds 1 for n≥3.

The article's accompanying bound M∥ΔA∥≤4np(1−p)+4 for every n≥1000 and p∈(0,1) is false. Specifically, at k=100, n=4k+2k!, p=1/n, every median of ∥ΔA∥=∥A−pJ∥ is at least 9, whereas 4np(1−p)+4<8. Here a median MZ means any real number with both P(Z≤MZ)≥1/2 and P(Z≥MZ)≥1/2.

Facts & Assumptions

[F1]

The loop-free graph law has independent Bernoulli edge coordinates (The Erdős-Rényi finite random graph G(n,p)).

[F2]

The article chooses ΔA=A−pJ for G(n,p) (Centered graph matrices and reference degree).

[F3]

The affine norm map is convex and has sharp cube Lipschitz constant 2(n−1)/n (The sharp coordinate constant already occurs inside the Bernoulli cube).

[F4]

At n=4k+2k! and p=1/n the probability of a vertex with at least k neighbors is at least 4/5 (A large degree with explicitly bounded probability at fixed sparse density).

[F5]

A graph with a vertex of degree at least k satisfies ∥A−J/n∥≥k−1 (A high-degree vertex forces a large centered adjacency norm).

Proof

Given: The hypotheses and objects in the Statement.

Goal: Establish the asserted conclusions.

1.1F1F2F3given

The edge-coordinate representation is [F1], with the centering identified by [F2]. Apply [F3] to obtain the asserted convexity and sharp Lipschitz constant. Its explicit two points lie in the actual cube; hence replacing the global domain by the Bernoulli coordinate cube does not restore the 1-Lipschitz assertion.

2.1F1F2F4F5givenalgebra∎

Choose k=100 and the displayed n,p. Then n is an even integer exceeding 1000 and 0<p<1, so the original median assertion applies to these parameters. By [F4] and [F5], Z=∥ΔA∥≥9 on an event of probability at least 4/5. If m<9, then P(Z≤m)≤1/5<1/2. Consequently every median is at least 9. Meanwhile np(1−p)=1−1/n<1, so 4np(1−p)+4<8. This is a concrete counterexample under the original hypotheses.

Source notes

The original article, PDF p. 35, proof of Corollary 6.6, says “It is not hard to see that f is convex and 1-Lipschitz” and then states the median bound refuted above. The definitions of J, ΔA, the choice d∗=pn, and the operator norm are in Section 1.2, PDF p. 6; the independent-edge model is described on PDF p. 4.

The local proof establishes the sharp coordinate constant and the counterexample to the displayed median bound under its full original quantifiers.

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