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Kraus rank equals Choi rank

PDF p. 3: Second paragraph, Ref. [43]

Statement

Let H and K be finite-dimensional complex inner-product spaces, with d=dim⁡H>0, and let N:L(H)→L(K) be a quantum channel, meaning a completely positive trace-preserving linear map. Fix an ordered orthonormal basis (ei)i=1d of H. A Kraus representation is a finite family of linear maps Aa:H→K satisfying N(X)=∑aAaXAa† for every X∈L(H). Its Kraus rank is the minimum number of operators in such a representation. Define the input-first, unnormalized Choi matrix by J=∑i,j=1d∣ei⟩⟨ej∣⊗N(∣ei⟩⟨ej∣). Then the Kraus rank of N equals rank⁡J.

Facts & Assumptions

Given: The spaces, channel, basis and Choi matrix in the Statement.

Goal: Show that the minimum size of a Kraus representation equals rank⁡J.

[F1]

For these finite-dimensional spaces and this Choi convention, the canonical Choi decomposition gives a Kraus representation with r=rank⁡J operators, and every Kraus representation has at least r operators. Canonical Choi eigenvectors, Kraus rank and branch weights

[F2]

The Kraus rank is the minimum size of a finite Kraus representation, and the displayed formula is the input-first, unnormalized Choi convention. Kraus rank and Choi representation

Proof

Given: The spaces, channel, basis and Choi matrix in the Statement.

Goal: Show that the minimum size of a Kraus representation equals rank⁡J.

1.1givenF1F2

The spaces, channel and basis satisfy the hypotheses of [F1], and the Choi matrix in [F1] is the matrix J of the Statement by [F2]. Thus a Kraus representation with r=rank⁡J operators exists, while every such representation has at least r operators.

2.1F2step 1.1∎

By the definition in [F2], the minimum representation size is therefore both at most and at least r. It equals r=rank⁡J, as claimed.

Depends on

Used by · 2

Dependency tree · 2 levels

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