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Kraus rank equals Choi rank
PDF p. 3: Second paragraph, Ref. [43]
Statement
Let and be finite-dimensional complex inner-product spaces, with , and let be a quantum channel, meaning a completely positive trace-preserving linear map. Fix an ordered orthonormal basis of . A Kraus representation is a finite family of linear maps satisfying for every . Its Kraus rank is the minimum number of operators in such a representation. Define the input-first, unnormalized Choi matrix by . Then the Kraus rank of equals .
Statement references
Facts & Assumptions
Given: The spaces, channel, basis and Choi matrix in the Statement.
Goal: Show that the minimum size of a Kraus representation equals .
For these finite-dimensional spaces and this Choi convention, the canonical Choi decomposition gives a Kraus representation with operators, and every Kraus representation has at least operators. Canonical Choi eigenvectors, Kraus rank and branch weights
The Kraus rank is the minimum size of a finite Kraus representation, and the displayed formula is the input-first, unnormalized Choi convention. Kraus rank and Choi representation
Proof
Given: The spaces, channel, basis and Choi matrix in the Statement.
Goal: Show that the minimum size of a Kraus representation equals .
The spaces, channel and basis satisfy the hypotheses of [F1], and the Choi matrix in [F1] is the matrix of the Statement by [F2]. Thus a Kraus representation with operators exists, while every such representation has at least operators.
By the definition in [F2], the minimum representation size is therefore both at most and at least . It equals , as claimed.
Depends on
Dependency tree · 2 levels
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Sources
- Monolithic Quantum Error Correction in the Presence of Distinguishability · PDF p. 3, second paragraph