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Endpoint correction and small-ball contraction estimates
PDF p. 14: Theorem 3.7 proof, endpoint identities and estimates; PDF p. 15: contraction estimate at top
Statement
Assume the Axiom of Choice and the geometry, parameters, control space , selector , endpoints , and maps of Endpoint-correcting nonlinear feedback map. In particular, obeys the three estimates of Abstract nonlinear control-space hypotheses with , and evaluation into has norm at most one. Give the sum norm, and put . Let be a bound for multiplication by on , and define and .
For every , and ; also and . The estimates are
For , put . If and , then maps the closed radius- ball of into itself and is a contraction there with constant at most . It consequently has exactly one fixed point in that ball, with endpoints . No uniqueness outside the ball is asserted.
Facts & Assumptions
The feedback definition gives , , and , where is the retarded forcing operator. It also gives and identifies the homogeneous and control terms with the linear solution steered by . Endpoint-correcting nonlinear feedback map
The perturbation hypotheses bound and by , bound the nonlinear size and difference by times the powers displayed in their definition, and bound terminal evaluation by one. Abstract nonlinear control-space hypotheses
Multiplication by the real cutoff is bounded on under the stated geometry and Choice assumptions. Cutoff multipliers through order two and by duality The Axiom of Choice
The endpoint feedback lemma records the selector identity and endpoint correction for the same homogeneous and control solution maps; its Banach-space formulation applies to complex spaces regarded as real spaces. A bounded endpoint selector yields small nonlinear exact steering
A contraction of a nonempty complete metric space into itself has exactly one fixed point there. A contraction of a nonempty complete metric space into itself has exactly one fixed point, the limit of the iterates from any starting point
Proof
Given: The stated feedback construction and its hypotheses, with the indicated endpoint data.
Goal: Prove the endpoint identities and estimates, and the claimed invariant-ball contraction.
The selector steers from to . Adding , which vanishes at time zero, gives and . Linearity of gives . These are the same solution and selector maps as in the endpoint feedback lemma.
Since multiplication by preserves the norm of , the forcing and nonlinear estimates give . Similarly, . These estimates apply to the forcing before and do not require multiplication by to preserve a real .
The selector and multiplier bounds imply . Terminal evaluation is bounded by one. Combining this with the homogeneous and forcing bounds and step 1.2 yields the asserted size estimate with ; also bounds the coefficient of .
The selector difference in step 1.1, terminal evaluation, and the same forcing and multiplier bounds give . The difference estimate follows from step 1.2 and the definition of .
If both endpoint norms are at most and , then step 2.1 gives . For two points in the ball, step 2.2 gives a Lipschitz constant at most . Because and are fixed, a positive satisfying the displayed smallness condition exists.
The ball is nonempty and complete: it contains zero, and a Cauchy sequence in it converges in the Banach space to a point still in the ball by the triangle inequality. The contraction theorem gives exactly one fixed point in this ball. Its endpoint values are those in step 1.1. This proves the stated conclusion without asserting uniqueness outside the ball.
Source notes
The frozen article, PDF pages 14–15, is cited for attribution of these estimates and the choice of constants. The deduction above uses the stated definitions and mathematical suppliers.
Depends on
- Endpoint-correcting nonlinear feedback map
- Abstract nonlinear control-space hypotheses
- Cutoff multipliers through order two and by duality
- A bounded endpoint selector yields small nonlinear exact steering
- The Axiom of Choice
- A contraction of a nonempty complete metric space into itself has exactly one fixed point, the limit of the iterates from any starting point
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