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Trace-free three-dimensional coercivity for the logarithmic gradient

Statement

Let V be a three-dimensional real inner-product space and let k:V→V be symmetric, meaning ⟨kx,y⟩=⟨x,ky⟩ for all x,y∈V, and trace free, meaning tr⁡(k)=0. Write ∣x∣2=⟨x,x⟩ for vectors, ∥k∥op=max⁡∣x∣=1∣kx∣, and ∣k∣2=∑i=13∣kei∣2 for any orthonormal basis (ei)i=13. The last expression, whose basis independence is proved below, defines the Hilbert–Schmidt norm of k.

Then ∥k∥op2≤23∣k∣2. If v≥1 and K≥0 are real numbers and Z,Q,A∈V satisfy ∣Z∣2=v2−1, ∣Q∣≤Kv2 and vA=kZ+Q, then for every ε>0 one has ∣A∣2≤23(1+ε)∣k∣2+(1+ε−1)K2v2.

In particular, let (M,h) be a smooth three-dimensional Riemannian manifold, let v:M→(0,∞) be smooth, and fix p∈M. Identify V with (TpM,hp), put A=(grad⁡hlog⁡v)p, and use v(p) for the numerical v in the preceding hypotheses. Whenever those hypotheses and the vector identity hold at p, the same bound controls ∣grad⁡hlog⁡v∣h2(p), including when v(p)=1. The vector identity is an assumption of this application, not a conclusion about arbitrary functions v.

Facts & Assumptions

[F2]

The trace of an endomorphism is the basis-independent trace of its matrix; matrix trace is the sum of the diagonal entries. The basis-independent trace of an endomorphism of a finite-dimensional vector space The trace tr(A) as the sum of the diagonal entries

[F4]

For a smooth function f on a Riemannian manifold, hp((grad⁡hf)p,X)=dfp(X) for every X∈TpM. The Riemannian gradient is the metric dual of the differential

[F5]

Proof

Given: The symmetric trace-free map, the numerical vector relation, and, for the application, the stated smooth Riemannian data. Goal: Establish both coercivity bounds and their conditional gradient application.

1.1F1F5givenalgebra

For arbitrary x,y,z∈V and a,b∈R, set d=k(ax+by)−akx−bky. The assumed symmetry and [F5] give ⟨d,z⟩=⟨ax+by,kz⟩−a⟨x,kz⟩−b⟨y,kz⟩=0. Taking z=d and using positive definiteness yields d=0. Thus k is linear, and its symmetry makes it self-adjoint by [F1]. In particular, its endomorphism trace and operator norm are defined before they are used below.

2.1F1F3step 1.1givenalgebra

By [F1], an orthonormal basis exists. For two such bases write fj=∑ioijei. Expanding each ei in the basis (fj) gives ∑joijoℓj=δiℓ, so ∑j∣kfj∣2=∑i,ℓ,joijoℓj⟨kei,keℓ⟩=∑i∣kei∣2. This proves that the finite sum defining ∣k∣2 is basis independent.

3.1F1F2F3step 2.1givenalgebra

By [F1], choose an orthonormal eigenbasis with eigenvalues λ1,λ2,λ3, ordered so that ∣λ1∣ is largest. In this basis [F2] and trace freeness give λ2+λ3=−λ1, and step 2.1 gives ∣k∣2=λ12+λ22+λ32. Since λ22+λ32≥(λ2+λ3)2/2, one obtains ∣k∣2≥32λ12. For x=∑ixiei, ∣kx∣2=∑iλi2xi2≤λ12∣x∣2, with equality at x=e1. Thus [F3] gives ∥k∥op2=λ12≤23∣k∣2.

4.1F3step 3.1givenalgebra

For vectors a,b and ε>0, expanding ∣εa−ε−1/2b∣2≥0 gives ∣a+b∣2≤(1+ε)∣a∣2+(1+ε−1)∣b∣2. Apply this to A=kZ/v+Q/v. The numerical hypotheses directly imply ∣Z∣2/v2=1−v−2≤1 and ∣Q∣/v≤Kv. By [F3] and step 3.1, ∣kZ∣2/v2≤∥k∥op2≤23∣k∣2. Substitution proves the claimed vector bound. Only division by v≥1 is used; if v=1, then Z=0 and the argument still applies.

5.1F4step 4.1given∎

In the stated Riemannian application, positivity and smoothness of v make log⁡v smooth, and [F4] defines A=(grad⁡hlog⁡v)p in the three-dimensional inner-product space (TpM,hp). The assumed pointwise vector identity and bounds therefore satisfy precisely the hypotheses of step 4.1 with the scalar v(p). That step proves the asserted gradient bound, also at v(p)=1. No differential identity has been inferred from the numerical assumptions.

Source notes

The Appendix B reference motivates the trace-free method. Its arcosh argument uses v>2; the present pointwise algebra divides only by v and proves the conditional bound for every v≥1.

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External dependencies

Alexandru F. Radu, Rigidity of stationary black holes with small ADM angular momentum, arXiv:2610.09729v1 · Appendix B, proof of Lemma B.1, (B.8)–(B.10), printed/PDF pp.38–39

The proof bounds the square of the largest absolute eigenvalue of the trace-free three-dimensional second fundamental form by its squared norm with coefficient 2/3, then estimates the gradient of arcosh v.

Hypotheses: A spacelike maximal three-dimensional hypersurface, a future unit timelike observer, bounded background coefficients, and v>2 for the arcosh calculation.

Reading limits: Consulted PDF text on pp.38–39 around (B.8)–(B.10); screenshot requests failed. This is methodological background, not an imported all-v theorem. The present proof uses finite-dimensional algebra and an assumed vector identity; it does not differentiate v. Its conditional logarithmic-gradient application and validity at v=1 are established locally. No weighted maximum estimate is imported.

Sources