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Radial barrier, absorption and height decay

PDF p. 14: §3.2.1; (3.6)–(3.7); PDF p. 15: §3.2.1; (3.6)–(3.7)

Statement

Fix δ∈(0,1) and μ∈(0,1). Assume the candidate family, normalized Cartesian ends and uniform estimates of Asymptotic maximal graph equation and coefficients and Uniform asymptotic slope bound. In particular, each normalized graph height u~q tends to zero as rq=∣xq∣→∞, uniformly in direction for that fixed q; the sections are assumed to exist. Write Lqv=aqij∂ijv+bqj∂jv, using the coefficients supplied by the graph equation, evaluated on the given graph.

There are Rδ,μ and cδ,μ>0, independent of q∈[δ,1], such that Lq(rq−μ)≤−cδ,μrq−μ−2 for rq≥Rδ,μ. Fix any r∗≥Rδ,μ and put Mq(r∗)=max⁡rq=r∗∣u~q∣. There is a constant Kδ,μ independent of q and r∗ such that, for rq≥r∗, ∣u~q(xq)∣≤(Mq(r∗)+Kδ,μ/r∗)(r∗/rq)μ. If Cδ is a uniform constant in ∣∂xqu~q∣≤Cδrq−1/2, then Mq(r∗)≤4−μ(Mq(r∗)+Kδ,μ/r∗)+2Cδr∗. Consequently, for a fixed sufficiently large r∗, ∣u~q∣≤Cδ,μrq−μ on rq≥r∗, with Cδ,μ independent of q.

Facts & Assumptions

[F1]

On a common end the graph equation is Lqu~q=fq, with aqij=δij+O(rq−1), bqj=O(rq−2) and ∣fq∣≤Crq−3 uniformly in q. The principal coefficient is uniformly positive definite on a sufficiently distant common end. Asymptotic maximal graph equation and coefficients

[F2]

On a common end the normalized slope satisfies ∣∂xqu~q∣≤Cδrq−1/2 uniformly in q. Uniform asymptotic slope bound

[F3]

The normalized end uses rq=∣xq∣, and the graph-height normalization requires convergence to zero uniformly in angle for each fixed parameter. Stationary maximal graphs and normalized graph heights

Proof

Given: The family and hypotheses in the Statement.

Goal: Establish the radial barrier, comparison, absorption inequality and uniform height decay.

1.1F1F3algebra

In three Cartesian spatial dimensions, direct differentiation gives Δ(r−μ)=−μ(1−μ)r−μ−2, while ∣∂ir−μ∣≤Cμr−μ−1 and ∣∂ijr−μ∣≤Cμr−μ−2. The coefficient errors in [F1] therefore contribute at most Cδ,μr−μ−3. Since μ(1−μ)>0, increasing the common radius gives the claimed strictly negative bound, uniformly in q.

2.1F1F3step 1.1algebra

Fix r∗ beyond that radius and choose Kδ,μ>C/cδ,μ, with C from [F1]. Set B=(Mq(r∗)+Kδ,μ/r∗)(r∗/r)μ. Then Lq(±u~q−B)>0 for r≥r∗: indeed −LqB is strictly greater than Cr−3 because r≥r∗ and μ<1. At the inner sphere ±u~q−B≤0. For each fixed q, [F3] and B→0 imply that on a sufficiently distant outer sphere this difference is at most any prescribed ε>0. On the closed intervening annulus it cannot attain a positive interior maximum exceeding ε: at such a maximum the gradient vanishes and the Hessian is negative semidefinite, so positive definiteness of aq gives Lq(±u~q−B)≤0, a contradiction. Letting the outer radius tend to infinity and then ε↓0 proves the comparison bound.

3.1F2step 2.1algebra

Along each radial segment from radius r∗ to 4r∗, [F2] bounds the height change by Cδ∫r∗4r∗s−1/2 ds=2Cδr∗. Taking the maximum over directions and applying step 2.1 at radius 4r∗ yields the stated absorption inequality.

4.1step 2.1step 3.1algebra∎

Since 1−4−μ>0, the inequality in step 3.1 gives a bound on Mq(r∗) independent of q once the common r∗ is fixed. Substitution into step 2.1 gives the asserted Cδ,μr−μ bound.

Source notes

The article reference attributes the original estimates. The proof does not use that reference as a premise; the comparison argument is given on bounded annuli and uses each individual graph's end limit, not a uniform rate of convergence in q.

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