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A unit-induced integral field coefficient zigzag

PDF p. 17: Corollary 6.9; integral Chern and support comparison

Statement

Fix a perfect field k. Write HSpi for Spitzweck's integral field spectrum, HA=s0KGLk, and U=s01k. There is a specified zigzag of unital motivic ring equivalences HSpi←uSpiU→uKHA. Both arrows are induced by units and the zeroth-slice functor. Their integral equivalence, including in characteristic p, is justified below using the canonical rank construction over Spec⁡Z and base change, rather than inferring it from a product-compatible field coefficient model. The shifted graded coefficient maps preserve products, units and the unit-adjoint reduced P1 class, with the same Tate-coordinate convention on both sides.

Facts & Assumptions

[F1]

Exact primary unit, Picard and smooth-purity inputs for field compatibility imports BEM Corollary9.7, which gives the integral E∞ unit equivalence uK and the base-change equivalence g∗s01Z≃s01k, for g:Spec⁡k→Spec⁡Z. No prime is inverted.

[F2]

Bachmann, The very effective covers of KO and KGL over Dedekind schemes, Theorem1.1(1), Example1.3 and Lemma2.1, give over Z the canonical map Σfr∞Vect≃f0KGL and the equivalence induced by rank (Σfr∞Vect)/β⟶Σfr∞Z≃HSpi. Here f1HSpi=0 holds over the Dedekind base Z as explicitly stated with Theorem1.1; the 1/2 assumption belongs only to the separate KO assertion. Bott periodicity identifies the displayed cofiber with s0KGLZ.

[F3]

Hoyois, The localization theorem for framed motivic spaces, Theorem21 and proof, identify Σfr∞Z with Spitzweck HZ by a natural E∞ equivalence, adjoint to the actual ring isomorphism on constant integers. It sends the rank-one constant to the ring unit, and is stable under arbitrary base change. Spitzweck Remark11.2 supplies the canonical unit-induced E∞ map uSpi:s01→s0HSpi≃HSpi over fields. The integral zero-slice/effectivity facts also hold over Z by [F2]–[F3].

Proof

Given: The stated integral spectra and maps, the existing universes.

Goal: Establish the actual first arrow as an integral equivalence with its unit, independently of an unread characteristic range of the classical sphere-slice theorem.

1.1F2F3

Over Z, use [F2] to obtain the equivalence a:s0KGLZ→HSpi,Z. Its construction is rank on the framed vector-bundle model followed by the equivalence of [F3]. The vector-bundle tensor unit is O, whose rank is the constant1. Consequently the composite of the sphere unit through f0KGL, its Bott cofiber, and a is the actual unit of HSpi, by the adjunction construction in [F3]. This is a unit triangle of actual maps, not an inference that an arbitrary equivalence preserves units.

2.1F1F2F3step 1.1

Let b:s01Z→HSpi,Z be the map induced by that unit. Because HSpi,Z is effective and has f1=0, maps from s01 to it are identified with maps from the effective unit: the f11 term is orthogonal to a zero-slice target. Thus the triangle in step 1.1 identifies b with a∘uK,Z. Both factors are integral equivalences by [F1]–[F2], so b is an equivalence. Its E∞ structure is the one supplied by multiplicative slices and the actual unit; no multiplicative structure on an arbitrary chosen Bott quotient is required for this inference.

3.1F1F2F3step 2.1

Pull this unit triangle back along g. Spitzweck HZ is absolute, and BEM Corollary9.7 identifies g∗s01Z with s01k. Naturality of units and slice comparison identifies the resulting map with the canonical uSpi,k in [F3]: both factor the same unit into the field zero-slice target. Hence this particular map is an integral equivalence. Together with the integral uK of [F1] it gives the claimed zigzag. This argument never uses a characteristic-zero theorem to assert an integral characteristic-p result.

4.1F1F3step 3.1∎

By BEM Remark 3.21 and Remark 3.23 in [F1], the normalized reduced P1 class of a motivic ring E is adjoint to T→E⊗T induced by its unit. Since the two maps of the zigzag are the actual unital ring maps, they preserve this class. Spitzweck Proposition11.1/Lemma6.6 identify its original Picard normalization; the later Picard-space detection and EM comparison helpers therefore apply unchanged.

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