Alphabeta Math
LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Generic local rings of reduced schemes

PDF p. 10: Dense smooth locus in Lemma 5.1

Statement

Assume the Axiom of Choice. Let X be a reduced scheme and let η be the generic point of an irreducible component. Then OX,η is a field.

A scheme is reduced when its local rings have no nonzero nilpotents. A generic point of a closed irreducible subset is a point whose closure is that subset.

Facts & Assumptions

Given: AC, a reduced scheme X and a generic point η of an irreducible component.

Goal: Show that OX,η is a field.

[F1]

On U=Spec⁡A, the local ring at the point corresponding to a prime p is Ap (The stalk of the affine structure sheaf at a prime is the localization at that prime).

[F2]

Under AC the nilradical is the intersection of all prime ideals (The nilradical is the intersection of all prime ideals). Choice is used only through this supplier (The Axiom of Choice).

Proof

1.1F1givenchoose

Choose an affine neighborhood U=Spec⁡A of η, corresponding to p. If q⊊p were prime, the closure in X of the point of U corresponding to q would be irreducible and strictly contain the closure of η: its intersection with U contains the point q, whereas the closure of η does not. This contradicts maximality of the component. Thus p is minimal.

2.1F1F2step 1.1given∎

The primes of Ap correspond to primes of A contained in p, so its only prime is its maximal ideal. The nilradical of a ring is the intersection of its prime ideals; consequently that maximal ideal is the nilradical. Reducedness of X makes this local ring reduced, so the ideal is zero. A local ring with zero maximal ideal is a field.

Depends on

Used by · 1

Dependency tree · 3 levels

Arrows run from prerequisites to the items that use them. External source nodes link directly to the cited text. The view shows up to three dependency steps; open a prerequisite to continue.