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The first two perfect Chern classes vanish on the third image piece in full scope
PDF p. 14: Lemma6.4; scheme conventions p3
Statement
Assume the Axiom of Choice and the fixed site and universe bounds of the supplied constructions. For every qcqs -scheme over any field, every has rank zero and . This uses actual stage maps and needs neither normality nor an image-stage isomorphism.
Facts & Assumptions
Assume the Axiom of Choice as formulated in The Axiom of Choice and the stated size bounds. Choice and the fixed size bounds are inherited from the first-layer comparison in [F2] at step 1.1 and the actual second-fiber comparison in [F3] at step 2.1.
Motivic filtration and image groups defines nested image groups. Stage projections, kernels and image groups gives the consecutive stage-to-layer fiber sequences.
The globally normalized first-layer Picard map is determinant and First Chern class factors through determinant identify the actual first layer with determinant/first Chern on the rank-zero space for all qcqs field-schemes.
Actual second-stage comparison on every qcqs field-scheme identifies the actual second layer with minus the actual second Chern operation in the same scope.
Proof
Given: and a third-stage representative , which exists by the image definition.
Goal: Prove lower-class vanishing without transporting projections through a finite-type image-stage identification.
Send to the second, first and zeroth stages. Their common augmentation is . Consecutive stage-to-layer composites are null by their fiber sequences. In particular its rank is zero, and the actual first-layer map of the first-stage representative is zero. By [F2] this gives .
Its second-stage representative is in the image of the third stage, so its actual second-layer value is zero. By [F3] that value is . Thus . No injectivity of any stage augmentation or representation of by global bundles has been used.
Depends on
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