Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31
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C6C_6 and the disjoint union of two triangles have the same degree sequence but are not isomorphic

Statement refuted

The false statement FALSE: a finite simple graph is determined up to isomorphism by its degree sequence claims that a finite simple graph is determined up to isomorphism by its degree sequence.

Facts & Assumptions

Given: G=C6G=C_6 and H=C3˙C3H=C_3\mathbin{\dot\cup}C_3, the disjoint union of two triangles.

[F2]

Isomorphisms preserve adjacency and therefore preserve path-reachability and connectedness (Graph isomorphisms, automorphisms and graph complements, Connected graphs and connected components defined by the existence of vertex paths).

Counterexample

technique · direct
1.1

Every vertex of GG lies on the six-cycle and has degree 22. Every vertex of HH lies on one of its two triangles and has degree 22. Thus both degree sequences are (2,2,2,2,2,2)(2,2,2,2,2,2).

givenF1
1.2

The graph GG is connected, since either direction around the cycle gives a path between any two vertices. The graph HH is disconnected, since no edge joins its two triangles.

givenF1
2.1

By [F2], connectedness is invariant under isomorphism, so G≇HG\not\cong H. They have the same degree sequence by step 1.1, which refutes the stated claim.

step 1.1step 1.2F2

Remarks

G=C6onecomponentH=C3_[C3twocomponentseverydisplayedvertexhasdegree2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 15 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources