Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedPipeline-generatedprecheck passverified 2026-09-23 (gpt-6-sol)
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A cohomology class obstructs a global symplectomorphism

Counterexample

Let ω be the standard positive area form on S2. The symplectic manifolds (S2,ω) and (S2,2ω) are not symplectomorphic.

Facts & Assumptions

Given: The oriented sphere and its positive area form.

[F1]

A symplectomorphism f must satisfy f∗ω1=ω0. Symplectomorphisms, local symplectomorphisms, and symplectic embeddings.

[F2]

On a compact connected oriented surface, integration identifies top de Rham cohomology with R. Integration is an isomorphism on top compactly supported de Rham cohomology.

[F3]

Positivity of the oriented integral gives a strictly positive choice-free finite-chart integral for a nonzero positive top form on compact S2.

[F4]

Change of variables on oriented manifolds gives the signed choice-free finite-chart integral identity for a diffeomorphism and a compactly supported top form, including the orientation-preserving case used here.

Verification

technique · direct
1.1F2F3givenalgebra

Both forms are closed and positive, hence symplectic. By [F3] the integral A=∫S2ω is strictly positive; by [F2], their cohomology classes are distinct because their integrals are A and 2A.

2.1F1F4step 1.1∎

If f∗(2ω)=ω, then f is orientation preserving because both forms are positive. The choice-free change-of-variables formula [F4] gives A=∫S2f∗(2ω)=2A, impossible. Thus [F1] fails for every diffeomorphism, exhibiting the global cohomology obstruction.

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