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Compact does not imply Hilbert Schmidt
Statement refuted
Assume the Axiom of Countable Choice (The Axiom of Countable Choice ()). Let with standard basis and define the diagonal operator extended linearly and by continuity. Then is compact (Compact linear operator) but not Hilbert–Schmidt relative to any Hilbert basis (Hilbert–Schmidt operator and Hilbert–Schmidt norm); that is, compactness does not imply the Hilbert–Schmidt property.
Facts & Assumptions
Given: Countable Choice, the space with its standard basis , and the diagonal operator with , for .
Diagonal criteria. For a diagonal operator with bounded sequence , boundedness, compactness, the Hilbert–Schmidt criterion relative to the standard basis, and the trace-class criterion hold as in the diagonal example; the Hilbert–Schmidt property and norm are basis-independent, and the standard basis is orthonormal with (Diagonal Schatten class criteria on ell two, Hilbert–Schmidt operator and Hilbert–Schmidt norm, The Hilbert–Schmidt norm is basis independent, Square-summable families on an arbitrary index set and the space ).
Divergence and convergence of -series. For rational the series converges, while at the harmonic series diverges; in particular is not summable because its terms dominate the harmonic terms for (For rational , converges iff ).
Countable Choice is the standing hypothesis (The Axiom of Countable Choice ()).
Counterexample
Given: Countable Choice, the sequence , , and the diagonal operator .
is compact. The sequence tends to (given rational , choose a natural ; then for ), so by the diagonal compactness criterion [A1] the operator is compact.
is not Hilbert–Schmidt. Relative to the standard basis, by the divergence of the harmonic series [A2], so is not Hilbert–Schmidt relative to the standard basis by the diagonal criterion [A1]; since the Hilbert–Schmidt property and its norm are independent of the chosen Hilbert basis [A1], is not Hilbert–Schmidt relative to any Hilbert basis.
Conclusion. The operator is compact by [step 1.1] and fails to be Hilbert–Schmidt by [step 1.2]; hence compactness does not imply the Hilbert–Schmidt property.
Depends on
- Diagonal Schatten class criteria on ell two
- For rational $p > 0$, $\sum 1/k^p$ converges iff $p > 1$
- Hilbert–Schmidt operator and Hilbert–Schmidt norm
- The Hilbert–Schmidt norm is basis independent
- Compact linear operator
- Trace class operator
- Square-summable families on an arbitrary index set and the space $\ell^2(I)$
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
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