Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-10-02
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A nontrivial degree-zero line bundle has no nonzero section

Counterexample

Assume the Axiom of Choice (The Axiom of Choice), inherited from the Cartier-Weil, genus, finite-map and function-field suppliers. Let k be an algebraically closed field and let E=V+(y2z−x3−axz2−bz3)⊆Pk2 be a smooth plane cubic, a curve of genus one (Arithmetic genus of a plane curve), with distinct closed points P,Q∈E. Then the invertible sheaf L=OE(P−Q) (Invertible sheaf of cartier divisor) has degree zero, H0(E,L)=0, and L is nontrivial: a nonzero section would present L as OE(D) with D effective and deg⁡D=0, forcing D=0 and L≅OE, while nontriviality holds because OE(P−Q)≅OE would give a rational function of divisor P−Q and hence a degree-one map E→P1, impossible for a curve of genus one. So degree zero neither forces triviality nor produces sections.

Facts & Assumptions

Given: An algebraically closed field k, the smooth plane cubic E=V+(F) with F=y2z−x3−axz2−bz3, and distinct closed points P,Q∈E.

[F1]

Let X=V+(G)⊆Pk2 be cut out by a nonzero homogeneous form of degree d≥1 and assume X is a curve (integral of dimension one); then H0(X,OX)=k and pa(X)=1−χ(OX)=(d−1)(d−2)2. In particular a smooth plane cubic is an integral proper curve with pa=1, and a line has pa=0. (Arithmetic genus of a plane curve)

[F2]

A curve over k is geometrically integral, separated, finite type of chain dimension one; a smooth proper curve is in particular integral and reduced, and the arithmetic genus pa(X)=1−χ(OX) of an integral proper curve is an invariant of its isomorphism class, because the cohomology of the structure sheaf depends only on the scheme up to isomorphism. (Curves over a field, Genus and arithmetic genus of a curve)

[F3]

On a smooth curve divisors are finite Z-combinations of closed points, deg⁡k(∑xnx[x])=∑xnx[κ(x):k], and over an algebraically closed field every closed point has residue field k and degree one. (Divisors on a smooth proper curve, Degree divisor proper curve)

[F4]

For a smooth proper geometrically integral curve C: the group Pic⁡(C) of isomorphism classes of invertible sheaves is identified with the divisor class group by [D]↦[OC(D)], the degree deg⁡k descends to a homomorphism Pic⁡(C)→Z taking OC(D) to deg⁡kD, and OC(D)≅OC(D′) if and only if D and D′ are linearly equivalent; the sheaf OC(D) is the invertible sheaf attached to the Cartier divisor D. (Cartier and Weil divisors agree on a smooth curve, The degree of a divisor descends to the Picard group of a normal proper curve, Invertible sheaf of cartier divisor)

[F5]

A nonzero rational section s of an invertible sheaf M on a smooth curve C determines a divisor div⁡(s) with M≅OC(div⁡(s)) carrying the canonical section 1 to s; consequently nonzero global sections of M correspond to effective divisors D with OC(D)≅M. (Rational sections of line bundles are Cartier divisors, Effective divisors linearly equivalent to D are sections modulo scalars)

[F6]

If D is an effective divisor on a proper geometrically integral curve over k, then deg⁡kD≥0, and deg⁡kD=0 if and only if D=0. (Effective divisors have nonnegative degree)

[F7]

A nonconstant rational function f∈k(C)× on a smooth proper geometrically integral curve defines a finite morphism φf:C→Pk1 whose degree is [k(C):k(f)] and whose fibre over infinity is the pole divisor (f)∞, of the same degree. (A nonconstant rational function defines a finite map to the projective line, Degree of a nonconstant morphism of curves)

[F8]

Under Choice the assignment f↦f∗ is a bijection from dominant morphisms between smooth proper geometrically integral curves over k onto injective k-algebra homomorphisms of function fields, and every birational rational map between smooth proper geometrically integral curves is represented by a k-isomorphism. (Smooth proper curves, dominant morphisms and function fields, Birational smooth proper curves are isomorphic)

[F9]

The Axiom of Choice: every family of nonempty sets has a choice function. (The Axiom of Choice)

[F10]

Polynomial rings in finitely many variables over a field are UFDs; irreducibles are prime. A nonzero positive-degree plane hypersurface has pure dimension one. Closed immersions and projective-space structure maps are proper, and proper morphisms compose. (Every finite-variable polynomial ring over a field is a UFD, with prime irreducibles and principal height-one primes, Nontrivial projective hypersurface sections, Finite-dimensional projective space is proper over every base, Closed immersions are proper, Properness survives composition)

Proof

technique · direct; show the curve has $p_a=1$ while a trivial class would force a degree-one map to $\mathbb P^1$
1.1F1F2F10givenalgebra

Integrality and genus. On z=1 the equation is y2−(x3+ax+b). The cubic polynomial in x is not a square in k(x): its order at infinity is −3, while a square has even order. Hence the monic quadratic in y is irreducible over k(x) and, by clearing denominators in the UFD k[x], over k[x,y]. Its homogenization F is irreducible too: a nonconstant homogeneous factor becoming constant at z=1 would be a scalar power of z, but z does not divide F. Thus [F10] makes the homogeneous quotient a domain; its nonempty projective charts are domains with common generic point, so E is integral. It is of dimension one and proper by [F10]. Since k is algebraically closed it is geometrically integral, and it is smooth by hypothesis, so [F1] applies with d=3 to give H0(E,OE)=k and pa(E)=1.

1.2F3F4

The class has degree zero. The closed points P,Q are k-rational, so [κ(P):k]=[κ(Q):k]=1 by [F3]; hence deg⁡k(P−Q)=deg⁡k(P)−deg⁡k(Q)=1−1=0, and by [F4] the invertible sheaf L=OE(P−Q) has deg⁡(L)=deg⁡k(P−Q)=0.

2.1F1F2F4F7F8step 1.1

The class is nontrivial. Suppose OE(P−Q)≅OE; by [F4] this means that P−Q=div⁡(f) for a rational function f∈k(E)×, so the pole divisor (f)∞ of f is the single point Q with multiplicity one and the divisor of f is nonzero; in particular f is nonconstant, and by [F7] it defines a morphism φf:E→Pk1 of degree [k(E):k(f)]=deg⁡k(f)∞=1. Consequently k(E)=k(f) is a degree-one extension of k(f), so φf is birational as a morphism of integral curves and [F8] represents it by a k-isomorphism E≅Pk1. The arithmetic genus is an isomorphism invariant [F2], so pa(E)=pa(Pk1)=0 by [F1] applied to a line, contradicting pa(E)=1 from step 1.1. Hence L is nontrivial.

3.1F4F5F6step 1.2step 2.1

Every nonzero section forces triviality. Suppose s∈H0(E,L) is nonzero. By [F5] there is an effective divisor D=div⁡(s) on E with OE(D)≅L; by [F4] the degree of L is deg⁡kD, which is 0 by step 1.2. So D is an effective divisor of degree zero, and [F6] forces D=0; then L≅OE(D)≅OE, contradicting the nontriviality of L from step 2.1. Therefore H0(E,L)=0.

4.1F9step 1.2step 2.1step 3.1∎

Conclusion. For distinct closed points P,Q on the smooth plane cubic E of genus one, the invertible sheaf L=OE(P−Q) has degree deg⁡k(P−Q)=0 by steps 1.2, is nontrivial by step 2.1, and has no nonzero global section by step 3.1: degree zero neither forces a line bundle to be trivial nor guarantees that it has a section. The Axiom of Choice is inherited from the Cartier-Weil, genus, finite-map and function-field suppliers [F9] and no further choice is used.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

192 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources