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An integrable based module can have no finite based envelope of a raw basis vector

Statement refuted

Every based integrable module for a quantum group of finite Cartan type contains, for each finite subset of its raw basis, a finite-dimensional U-submodule spanned by a subset of that same raw basis and containing the given subset.

The assertion fails already for Uq(sl2) and a singleton seed. Here “based” means the four axioms of The bar lattice and the divided-power integral lattice of a based module, with integrability in place of finite-dimensionality.

Facts & Assumptions

Given: U=Uq(sl2) over Q(q), A=Z[q,q−1], and the explicit based chain of Distinct cyclotomic shears give integrable based quantum sl-two chains.

[F1]

The chain supplier gives M=⨁j≥0V(nj), nj=j(j+3), with divided string vectors uj,k=F(k)uj,0, 0≤k≤nj. Put ℓj=j+3, rj=j+2, and pj=q−φ(2ℓj)/2Φ2ℓj(q)≠0. The supplier's shear maps satisfy Tjuj,0=uj+1,rj and vanish on positions not divisible by ℓj. With S=∑j≥0Tj/pj, one has S2=0 and C=1+S, C−1=1−S. The vectors bj,k=Cuj,k form the raw basis B of a genuine four-axiom based integrable module; all sums act with finite support (Distinct cyclotomic shears give integrable based quantum sl-two chains).

[F2]

On the divided string of V(N), E(h)uk=[N−k+hh]quk−h for 0≤h≤k, and the result is zero for h>k. In particular E(h)u0=0 for h>0. These formulas follow by iteration of Divided-power commutation and the simple Uqi(sl2) string modules; each displayed Gaussian coefficient with 0≤h≤k≤N is nonzero in Q(q).

[F3]

A based subobject is a U-submodule spanned by a subset of the raw basis (The bar lattice and the divided-power integral lattice of a based module). Consequently, if a vector belongs to a based subobject, every raw basis vector having nonzero coefficient in its basis expansion belongs to that subobject, by uniqueness of basis coordinates.

Counterexample

1.1givenF1

Take the actual based chain of [F1] and the singleton seed {b0,0}. Each vector of its field direct sum belongs to finitely many finite strings, so its U-orbit is finite dimensional. In particular b0,0=u0,0+u1,2/p0 belongs to V(0)⊕V(4). The seed therefore has a finite field orbit, while the question asks for a submodule spanned by raw basis vectors.

1.2F1F2algebra

For every j≥0, write Gj=[nj+1rj]q≠0. Since bj,0=uj,0+uj+1,rj/pj, [F2] gives E(rj)bj,0=(Gj/pj)uj+1,0. Furthermore uj+1,0=bj+1,0−uj+2,rj+1/pj+1. The index rj+1=j+3 is strictly between 0 and ℓj+2=j+5, so Tj+2uj+2,rj+1=0 and uj+2,rj+1=bj+2,rj+1. Thus the exact raw expansion is E(rj)bj,0=(Gj/pj)bj+1,0−(Gj/(pjpj+1))bj+2,rj+1. The two displayed raw vectors are distinct, and the first coefficient is nonzero.

2.1F3step 1.2algebra

Let W be any U-submodule spanned by a subset of B and containing b0,0. If bj,0∈W, its image under E(rj) belongs to W by U-stability, and the nonzero bj+1,0 coordinate in step 1.2 forces bj+1,0∈W by [F3]. Starting from j=0, induction therefore gives bj,0∈W for every j≥0. These are infinitely many distinct members of the field basis B, so W is infinite dimensional.

3.1step 1.1step 2.1F1∎

Hence no finite-dimensional based subobject of M contains the singleton seed b0,0. The module satisfies all four actual based axioms and is integrable in finite Cartan type by [F1], so it refutes the stated universal finite-envelope assertion.

Remarks

This counterexample concerns raw basis compatible submodules. It does not itself refute tensor globalization: a construction using finite correction supports could conceivably work without finite based submodules. The finite-dimensional based filtration in Lusztig §27.1 and the bounded extension in Bao–Wang Remark2.10 retain their own hypotheses.

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