Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-08-16
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The half graph has no regularity across its natural bipartition at a fixed small parameter

Statement

Let Xn={a1,…,an} and Yn={b1,…,bn}, with aibj an edge exactly when i≤j. For every n≥4, the natural pair (Xn,Yn) is not 1/5-regular.

Facts & Assumptions

Given: The displayed bipartite half graph.

[L1]

Failure of ϵ-regularity is witnessed by subsets of relative size at least ϵ whose density differs from the full-pair density by more than ϵ (ϵ-regular pairs and self-regular vertex sets).

[L2]

Counterexample

technique · direct
1.1givenalgebra

The number of cross-edges is n+(n−1)+⋯+1=n(n+1)/2, so d(Xn,Yn)=(n+1)/(2n).

1.2givenL2choosealgebra

Put q=⌈n/4⌉, A={a1,…,aq}, and B={bn−q+1,…,bn}. Then ∣A∣,∣B∣≥n/4>n/5, and every ai∈A satisfies i≤j for every bj∈B, so d(A,B)=1.

2.1step 1.1step 1.2L1algebra∎

For n≥4, one has ∣d(A,B)−d(Xn,Yn)∣=(n−1)/(2n)≥3/8>1/5. Together with the size bounds in step 1.2, [L1] shows that (Xn,Yn) is not 1/5-regular.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources