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CounterexampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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A bounded truncation function need not have an improper limit

Example

Define f(x)=(1)kf(x)=(-1)^k on [k,k+1)[k,k+1) for every nonnegative integer kk. Its truncation primitive is bounded, but 0f\int_0^\infty f diverges.

Facts & Assumptions

Verification

technique · counterexample
1.1

For a positive integer NN, additivity gives the displayed sum, whose parity values follow from the alternating sequence. [L1, L2] 0Nf=k=0N1(1)k,\int_0^Nf=\sum_{k=0}^{N-1}(-1)^k, which equals one for odd NN and zero for even NN by [L2]. Thus the integer truncations are bounded but have no limit. [L1, L2] If NR<N+1N\le R<N+1, the remaining integral has absolute value at most one, so the full truncation primitive is bounded as asserted.

2.1

An improper limit would restrict to the same limit along all integer truncations, contradicting step 1.1. The example changes sign, so it does not satisfy the nonnegativity hypothesis in [L3] and shows that hypothesis cannot be deleted.

L3step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 84 results over 23 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources