Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-08-31
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The punctured disc is connected but not simply connected

Statement refuted

Every connected subdomain of the unit disc is simply connected.

Facts & Assumptions

Given: The punctured disc Ω={z∈C:0<∣z∣<1} and the circle γ(t)=12eit on [0,2π].

[L1]
[L2]

A circle around the origin has winding number 1 about the origin (A circle traversed k times has winding number k inside and 0 outside).

Counterexample

technique · direct
1.1given

The punctured disc is open and connected, and the loop γ lies in it. Its spherical complement is the union of the singleton {0} and the outer region {∣z∣≥1}∪{∞}, so it is disconnected.

2.1step 1.1L1L2

By [L1], step 1.1 shows that the punctured disc is not simply connected. Fact [L2] gives the same geometric reason numerically: the loop γ still winds once around the omitted point 0.

3.1step 1.1step 2.1∎

This refutes the claim.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

42 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources