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Vanishing deformation tangent space does not force rigidity of the deformation groupoid

Statement refuted

Statement refuted. Let k be a field and let X be a flat, locally finitely presented k-scheme with Ext⁡OX1(LX/k,OX)=0. Then the deformation groupoid of X is trivial: every deformation of X over every local Artin k-algebra with residue field k is isomorphic to the trivial deformation by a unique isomorphism, and in particular the trivial deformation has no non-identity automorphisms reducing to the identity modulo the maximal ideal.

Facts & Assumptions

Given: a field k, the affine line X=Ak1=Spec⁡k[x], and the Axiom of Choice.

[F1]

The presentation k[x]=k[t]/(0) has no relations, so its empty Jacobian minor is 1; the Jacobian criterion makes Ak1 smooth over k (Relative Jacobian criterion with its presentation hypothesis). Also ΩAk1/k1≅OAk1 is free of rank one; hence LX/k≃ΩX/k1[0]. (Polynomial differentials are free, Truncation, differentials and the cotangent complex of a smooth morphism)

[F2]

For a locally free finite-rank F one has Ext⁡OXi(F,M)≅Hi(X,Hom(F,M)); in particular Ext⁡1(LX/k,OX)≅H1(X,OX) for F=ΩX/k1≅OX. (Ext of a locally free cotangent sheaf via sheaf cohomology)

[F3]

Higher quasi-coherent cohomology of the affine scheme Ak1 vanishes, so H1(Ak1,O)=0. (Affine acyclicity of quasi-coherent sheaves)

[F4]

Every deformation of X=Ak1 over every local Artin k-algebra with residue field k is isomorphic to the trivial deformation, because Ext⁡OX1(LX/k,OX)=0. (Vanishing of the deformation tangent space forces rigidity of deformation classes)

[F5]

The automorphism group of a deformation lift over a small extension is Ext⁡OX0(LX/A,OX⊗AI)≅Der⁡A(OX,OX⊗AI), and infinitesimal automorphisms of the trivial deformation over k[ϵ] are exactly the k[ϵ]-algebra automorphisms reducing to the identity. (Obstructions to deformations lie in Ext^2 of the cotangent complex, Deformations of algebras: obstruction in degree two and torsor structure in degree one, Derivation of an algebra, Deformations of schemes and the infinitesimal deformation functor)

Counterexample

technique · compute the vanishing of Ext^1 for the affine line, exhibit an explicit non-identity infinitesimal automorphism of the trivial deformation, and then use rigidity of deformation classes
1.1F1F2F3

The affine line has vanishing deformation tangent space. The affine line is quasi-compact and separated, so it satisfies the geometric hypotheses of [F4]. By [F1], LX/k≃ΩX/k1[0]≅OX[0], so [F2] and [F3] give Ext⁡OX1(LX/k,OX)≅H1(Ak1,OAk1)=0.

1.2F5givenalgebra

A non-identity infinitesimal automorphism. Consider the trivial deformation Spec⁡k[ϵ][x] over the dual numbers and the k[ϵ]-algebra endomorphism σ ⁣:k[ϵ][x]→k[ϵ][x], x↦x+ϵx2. It is a well-defined k[ϵ]-algebra map because x+ϵx2 is a polynomial; its inverse is τ ⁣:x↦x−ϵx2, since σ(τ(x))=x+ϵx2−ϵ(x+ϵx2)2=x+ϵx2−ϵx2=x and likewise τ(σ(x))=x because ϵ2=0. Moreover σ reduces to the identity modulo ϵ but σ(x)−x=ϵx2≠0, so σ is a non-identity automorphism of the trivial deformation reducing to the identity.

2.1F4step 1.1

All deformation classes are trivial. Since Ext⁡OX1(LX/k,OX)=0 by step 1.1, [F4] gives that for every local Artin k-algebra A with residue field k every deformation of Ak1 over Spec⁡A is isomorphic to the trivial deformation; this confirms the hypothesis and the Ext⁡1-part of the refuted statement.

3.1F4F5step 1.1step 1.2step 2.1∎

Identification with a derivation and conclusion. By [F5] the infinitesimal automorphism group of the trivial deformation is Ext⁡OX0(LX/k,OX)=Der⁡k(k[x],k[x])=k[x]∂x, which is infinite-dimensional; the automorphism σ of step 1.2 corresponds to the derivation x2∂x. Hence the deformation groupoid is not trivial and the trivial deformation is not rigid, although its tangent space vanishes by step 1.1 and all deformation classes are trivial by step 2.1. The correct statement is rigidity of isomorphism classes (Vanishing of the deformation tangent space forces rigidity of deformation classes); rigidity of the groupoid would require the additional vanishing of Ext⁡0, which fails here.

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